The 38-mm-diameter shaft ab is made of a grade of steel for which the yield strength is 250 mpa. v y using the maximum-shearing-
stress criterion, determine the magnitude of the torque t for which yield occurs when p 240 kn.
1 answer:
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Answer:
speed of electrons = 3.25 × m/s
acceleration in term g is 3.9 × g.
radius of circular orbit is 2.76 × m
Explanation:
given data
voltage = 3 kV
magnetic field = 0.66 T
solution
law of conservation of energy
PE = KE
qV = 0.5 × m × v²
v =
v =
v = 3.25 × m/s
and
magnetic force on particle movie in magnetic field
F = Bqv
ma = Bqv
a =
a =
a = 3.82 × m/s²
and acceleration in term g
a =
a = 3.9 × g
acceleration in term g is 3.9 × g.
and
electron moving in circular orbit has centripetal force
F =
Bqv =
r =
r =
r = 2.76 × m
radius of circular orbit is 2.76 × m