Explanation:
Sound waves are often simplified to a description in terms of sinusoidal plane waves, which are characterized by these generic properties:
Frequency, or its inverse, wavelength.
Amplitude, sound pressure or Intensity.
Speed of sound.
Direction.
The oceanic crust solidifies faster than the continental crust. Because when magma comes into contact with ocean water it cools faster than when it reaches continental rock. Option C is correct.
<h3>What is the crust?</h3>
The outermost layer of a terrestrial planet is referred to as its "crust."
In the upper mantle, the Earth's crust is constantly melting and solidifying. Compared to magma beneath the continental crust, the oceanic crust has a lower temperature.
Magma cools more quickly when it comes into touch with ocean water than when it hits continental rock. causes the continental crust to solidify more slowly than the oceanic crust.
Hence option C is correct.
To learn more about the crust refer;
brainly.com/question/13428623
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Answer:
true , true, and I'm not sure about the last one!
Explanation:
Answer:
4. It is infrared.
Explanation:
the photosystems on the chlorophyll absorb light at 600-700nm
Answer:
vf = 3.27[m/s]
Explanation:
In order to solve this problem we must analyze each body individually and find the respective equations. The free body diagram of each body (box and bucket) should be made, in the attached image we can see the free body diagrams and the respective equations.
With the first free body diagram, we determine that the tension T should be equal to the product of the mass of the box by the acceleration of this.
With the second free body diagram we determine another equation that relates the tension to the acceleration of the bucket and the mass of the bucket.
Then we equalize the two stress equations and we can clear the acceleration.
a = 3.58 [m/s^2]
As we know that the bucket descends 1.5 [m], this same distance is traveled by the box, as they are connected by the same rope.
![x = \frac{1}{2} *a*t^{2}\\1.5 = \frac{1}{2}*(3.58) *t^{2} \\t = 0.91 [s]](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2Aa%2At%5E%7B2%7D%5C%5C1.5%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%283.58%29%20%2At%5E%7B2%7D%20%5C%5Ct%20%3D%200.91%20%5Bs%5D)
And the speed can be calculated as follows:
![v_{f}=v_{o}+a*t\\v_{f}=0+(3.58*0.915)\\v_{f}= 3.27[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bo%7D%2Ba%2At%5C%5Cv_%7Bf%7D%3D0%2B%283.58%2A0.915%29%5C%5Cv_%7Bf%7D%3D%203.27%5Bm%2Fs%5D)
