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3 years ago

Answer lol! pls! !!!

Physics

2 answers:

Mila [183]3 years ago

6 0

Answer:

you thought this was a normal problem... BUT IT WAS ME D I O

Explanation:

i am confused and i makez meme

kogti [31]3 years ago

5 0

Answer:

Confused

Explanation:

more details

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What is acceleration?

bonufazy [111]

I'm pretty sure it's A.

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3 years ago

When cells use chemical energy obtained from food, this is known as

AnnyKZ [126]

It is respiration. Cell burns glucose with oxygen to release energy, along with producing water and carbon dioxide.

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3 years ago

Read 2 more answers

The earth has a mass of 5.98 × 10^24 kg and the moon has a mass of 7.35 × 10^22 kg. The distance from the centre of the moon to

Leokris [45]

Answer:

F = 4.48N

Explanation:

In order to calculate the net gravitational force on the rocket, you take into account the formula for the gravitational force between two objects, which is given by:

$F=G\frac{m_1m_2}{r^2}$ (1)

G: Cavendish's constant = 6.674*10^-11 m^3kg^-1s^-2

r: distance between the objects

You have a rocket at the middle of the distance between Earth and Moon, then, you have opposite forces on the rocket.

If you assume the origin of a system of coordinates at the rocket position, with the Moon to the left and the Earth to the right, you have:

$F=G\frac{M_em}{r_1^2}-G\frac{M_mm}{r_2^2}$ (2)

Me: mass of the Earth = 5.98*10^24 kg

Mm: mass of the Moon = 7.35*10^22 kg

m: mass of the rocket = 1200kg

r1: distance from the rocket to the Earth = 3.0*10^8m

r: distance between rocket and Moon = 3.84*10^8m - 3.0*10^8m = 8.4*10^7m

You replace the values of the parameters in the equation (2):

$F=Gm[\frac{M_e}{r_1^2}-\frac{M_m}{r_2^2}]\\\\F=(6.674*10^{-11}m^3kg^{-1}s^{-2})(1200kg)[\frac{5.98*10^{24}kg}{(3.0*10^8m)^2}-\frac{7.35*10^{22}kg}{(8.4*10^7m)^2}]\\\\F=4.48N$

The net force exerted over the rocket is 4.48N

4 0

3 years ago

A cylinder with rotational inertia I₁ = 2.4 kg · m² rotates clockwise about a vertical axis through its center with angular spee

miv72 [106K]

Answers :

Explanation:

Given that.

First cylinder data

Inertial I₁ = 2.4 kgm²

angular speed ω₁ = 5.8 rad/s.

Second cylinder data

inertia I₂ = 1.3 kgm²

angular speed ω₂ = 7.0 rad/s.

If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)?

So, the cylinder couple and move together with the same angular speed

Then, using conservation of angular momentum

L(final) = L(initial)

(I₁ + I₂) • ω = I₁•ω₁ + I₂ω₂

(2.4+1.3)•ω = 2.4 × 5.8 + 1.3 × 7

3.7•ω = 23.02

ω = 23.02 / 3.7

ω = 6.22 rad/s

The combine angular speed of the cylinder is 6.22 rad/s

8 0

3 years ago

Estimate the frequency of vibration of your arm.

Natali5045456 [20]

Answer:

0.7945 Hz

Explanation:

Data provided in the question:

Length of the arm = 0.59 m

Since the center of mass lies at about $\frac{2}{3}$ of its length

Thus,

Length of the simple pendulum = $\frac{2}{3}$ × 0.59 m = 0.3933 m

Now,

Frequency of vibration, f = $\frac{1}{2\pi}\sqrt\frac{g}{l}$

Thus,

we have,

Frequency of vibration for the arm = $\frac{1}{2\pi}\sqrt\frac{9.8}{0.3933}$

Frequency of vibration for the arm = 0.7945 Hz

5 0

3 years ago