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3 years ago

Explain Why must a cooling system do work to transfer thermal energy?

1 answer:

8 0

Although internal energy will not spontaneously flow from a cold region to a hot region, it can be forced to do so by doing work on the system.Refrigerators and heat pumps are examples of heat engines which cause energy to be transferred from a cold area to a hot area. Usually this is done with the aid of a phase change, i.e., a refrigerant liquid is forced to evaporate and extract energy from the cold area. Then it is compressed and forced to condense in the hot area, dumping its heat of vaporization into the hot area. ARE YOU FROM K12?

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An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of th

lawyer [7]

Answer:

28.3kg

Explanation:

45=0.88*ml1.4

36.6=0.88m

divide through by 0.88

is said that

m=36.6/0.88

m=28.2857kg

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3 years ago

Pravat exerts a force of 30 n to lift a bag of groceries 0.5 m. how much work did pravat do on the bag? note : work = force x di

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Answer in photo below

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2 years ago

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Which type of wave forms at the boundary between air and water when you

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D. Transverse wave

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3 years ago

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The part of a circuit that increases the electric potential of the electrons is the _____. . . . . conducting wires. resistors.

Readme [11.4K]

The part of a circuit that increases the electric potential of the electrons is the battery. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

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3 years ago

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he atomic radii of Li and O2- ions are 0.068 and 0.140 nm, respectively. (a) Calculate the force of attraction in newtons betwee

Crazy boy [7]

Answer:

$F = -1.07 *10^{-8} \ N$

$F_r = 1.07 *10^{-8} \ N$

Explanation:

Generally the force of attraction between this two irons is mathematically represented as

$F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}$

Here k is known as the proportionality constant with value $k = 2.31 * 10^ {-28} J \cdot m$

substituting -2 for $Q_{O}$ i.e the charge on oxygen , +1 for $Q_{Li}$ i.e the charge on Lithium and $[0.140 + 0.068 ] nm= 0.208 nm = 0.208*10^{-9}$ for r

$F = \frac{ 2.31 * 10^ {-28}* +1 * -2 }{ ( 0.208*10^{-9} )^2 }$

$F = -1.07 *10^{-8} \ N$

Generally the force of repulsion will be the magnitude but different direction to the force o attraction

So Force of repulsionn is

$F_r = 1.07 *10^{-8} \ N$

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4 years ago