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iris [78.8K]
2 years ago
15

I need help , sincerely appreciate it , anyone who could assist me

Mathematics
1 answer:
Olegator [25]2 years ago
4 0
The axis of symmetry is x=3
You might be interested in
Anyone feel like helping me??
Digiron [165]
The angles of a triangle add up to 180 degrees

65 + 3x - 10 + 2x = 180
5x + 55 = 180
5x = 180 - 55
5x = 125
x = 125/5
x = 25 <====

m < B = 3x - 10 = 3(25) - 10 = 75 - 10 = 65 <== B is 65 degrees
m < C = 2x......= 2(25) = 50 <== C is 50
8 0
3 years ago
Need help on these trig homework
allochka39001 [22]

8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

<h3>How to solve the trigonometry</h3>

8. We have the angle to be 20 degrees

Opposite side = x

hypotenuse = 23m

Using the sine ratio

sin θ = opposite/ hypotenuse

sin 20 = \frac{x}{23}

Cross multiply

sin 20 × 23 = x

x = 0. 3420 × 23

x = 7. 9 m

The length of the support is 7. 9 m

9. The angle of elevation is 37. 3 degrees

Hypotenuse = 19 . 0m

Opposite = x

Using the sine ratio

sin θ = opposite/ hypotenuse

sin 37. 3 = \frac{x}{19}

cross multiply

x = 0. 6059 × 19

x = 11.5

x = 12 m in 2 significant figures

The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

For side a, we use the Pythagorean theorem

c^2 = a^2 + b^2

85^2 = a^2 + 67^2

a = \sqrt{89^2-67^2}

a = \sqrt{3432}

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

\frac{59}{sin A } = \frac{85}{sin 90}

cross multiply

sin A × 85 = sin 90 × 59

make sin A subject of formula

sin A = \frac{59}{85}

sin A = 0. 6941

A = sin^-^1(0. 6941)

A = 44°

\frac{67}{sin B} = \frac{85}{sin 90}

cross multiply

sin B × 85 = sin 90 × 67

make sin b subject of formula

sin B = \frac{67}{85}

sin B = 0. 7882

B = sin^-^1( 0. 7882)

B = 52°

4. To find the sides, we use the sine rule;

\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}

Cross multiply

sin 56. 6 × c = sin 90 × 74

make 'c' subject of formula

c = \frac{74}{0. 8348}

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

c^2 = a^2 + b^2

b^2 = c^2 - a^2

b^2 = 88. 8^2 - 74^2

b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}

b = 49. 1 m

\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}

cross multiply

sin B = \frac{40. 99}{74. 0}

B = sin^-^1(0. 5539)

B = 34°

Learn more about trigonometric identity here:

brainly.com/question/7331447

#SPJ1

3 0
1 year ago
Which graph represents the function f(x)=4/x?
Vlada [557]
BbbbbbbbbbbbbbbsbsbsbabHsnabHbnasbsbsbsbnznznznznz
6 0
2 years ago
Sketch the algebra-tile shape at right on your paper. Write an expression for the
Dima020 [189]

Answer:

Part 1) P=(4x+4)\ units

Part 2)

a) P=32\ units

b) P=26\ units

c) P=13\frac{1}{3}\ units

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Part 1) Write an expression for the  perimeter of the shape

we know that

The figure is composed by a larger square, a rectangle and a smaller square

1) The area of the larger square is given

A=x^2\ units^2

so

The length and the width of the larger square is x units

2) The area of the rectangle is given

A=x\ units^2

so

The length of the rectangle is x units and the width is 1 unit

3) The length and the width of the smaller square is x units

see the attached figure N 2 to better understand the problem

Find out the perimeter

The perimeter is the sum of all the sides.

so

P=(x+x+x+x+1+1+1+1)

P=(4x+4)\ units

Part 2) Find the perimeter for each of the given values of x.

a) For x=7 units

Substitute the value of x in the expression of the perimeter

P=(4(7)+4)=32\ units

b) For x=5.5 units

Substitute the value of x in the expression of the perimeter

P=(4(5.5)+4)=26\ units

b) For x=7/3 units

Substitute the value of x in the expression of the perimeter

P=(4(\frac{7}{3})+4)=\frac{40}{3}=13\frac{1}{3}\ units

8 0
3 years ago
I need help please and thank you
ss7ja [257]

Answer:

increasing

Step-by-step explanation:

This line is increasing

The slope is greater than 0 so the line is going up

8 0
3 years ago
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