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Cerrena [4.2K]
2 years ago
9

Twice a number added to a smaller number is 5. The difference of 5 times the smaller number and the larger number is 3. Let

Mathematics
2 answers:
kykrilka [37]2 years ago
6 0

Answer:

The equations that represent the situation are:

2y+x=5

5x-y=3

Alchen [17]2 years ago
5 0

Answer:

2y+x=5

5x-y-3

Step-by-step explanation:

Two times of the larger number which is y is 2y added to the smaller number x is equal to 5 . Which is 2y+x=5

The difference of five times the smaller number and larger number is 5x-y

And the resulting answer is 3

ie..5x-y=3 , when the 3 crosses to the other side it becomes 5x-y-3=0

hence,the equation 5x-y-3

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grigory [225]
 \sqrt{ x^{2} }= -x
-x \geq 0 x \leq 0

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That is the answer
6 0
2 years ago
Marius combined 4/8 gallon of lemonade, 3/8 gallon of cranberry juice, and 6/8 gallon of soda water to make punch for a party. H
Xelga [282]

13/8, which you can also write as 1 5/8

5 0
2 years ago
A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
2 years ago
A community is considering raising funds to pay for improvements to the community swimming pool. To measure the
dezoksy [38]

Answer:

All residents of the community

Step-by-step explanation:

Not sure if this is fully correct but the 2nd and 3rd option is wrong (Edg 2021)

6 0
3 years ago
a 28 inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third pi
klasskru [66]
Where x is the length of the first piece
x + 2x + 6x + 1 = 28 \\  \\ 9x = 27 \\  \\ x = 3
so the first piece is 3 inches, the second is 6 inches and the third is 19 inches
3 0
3 years ago
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