Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
Well, if you look into it, inspect element thsi, really. I believe it is either A, Or C. But I am more strong with A.
The fractions you start with have to be re-written with the same (common) denominator.
For example, if you were asked to add 3/5 and 6/7, you would:
1) Identify the Lowest Common Denominator (LCD): Here it is 5*7 = 35.
2) Multiply both numerator and denom. of 3/5 by 7: 21/35
3) Mult. both num. and denom. of 6/7 by 5: 30/35
4) Combine these two equivalent fractions: 21/35 + 30/35 = 51/35 (answer)
Try a few such problems yourself and write back if you need further help.
Answer:
Step-by-step explanation:
Given that,
The height of the paper cone shaped, h = 33 cm
The diameter of the cone, d = 20 cm
Radius = (20/2) = 10 cm
oWe need to find how much paper was used. It means we need to find the total surface area of the cone.
Where
l is the slant height,
So,
So, 
of the paper was used.
1.2
0.035
0.6
4000
Mark brainliest please
Hope this helps you out
