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2 years ago

20 is 25% of what number? Enter your answer in the box.

Mathematics

2 answers:

schepotkina [342]2 years ago

8 0

Answer:

Step-by-step explanation:

Leni [432]2 years ago

4 0

Answer:

Step-by-step explanation:

25 percent is equal to 1/4

1/4 of 80 is 20

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Image of math question below

vitfil [10]

The second one

Hope this helps :D

7 0

2 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

4 divided by 5/9 = easy question big points lol

V125BC [204]

7.2 is answer thanks

5 0

2 years ago

Read 2 more answers

For what value of c does x^2−2x−c=4 have exactly one real solution? PLEASE HELP!!!!!!!

Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

$x^2-2x-(c+4)=0$ .

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic $ax^2+bx+d$ , the discriminant is $\sqrt{b^2-4ad}$ .

(The discriminant is more commonly known as $\sqrt{b^2-4ac}$ , but I changed the variable since we already have a $c$ in the quadratic given.)

In the quadratic above, we have $a=1$ , $b=-2$ , and $d=-(c+4)$ . Plugging this into the formula for the discriminant, we have

$\sqrt{(-2)^2-4(1)(-(c+4))$ .

Using the distributive property to expand and simplifying, the expression becomes

$\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.$

Setting the discriminant equal to 0 gives

$2\sqrt{c+5}=0$ .

We can then solve the equation as usual: first, divide by 2 on both sides:

$\sqrt{c+5}=0$ .

Squaring both sides gives

$c+5=0$ ,

and subtracting 5 from both sides, we have

$\boxed{c=-5}.$

3 0

2 years ago

Suppose you want to know how fast you traveled from the park to the library. As you moved, your speed varied from second to seco

frutty [35]

Step-by-step explanation:

In order to describe speed of an object, we must describe the average speed of the entire trip. It is equal to the distance moved divided by time taken.

If a person covers a distance of 1 km to the library in 15 minutes, we can find its average speed.

Firstly, we convert 15 minutes to hour, 15 min = 0.25 hours

Now, using formula of speed = distance/time

$v=\dfrac{1\ km}{0.25\ h}\\\\v=4\ km/h$

It means that the average speed of the person is 4 km/h. Hence, the given statement is true.

6 0

2 years ago