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3 years ago

What is the measure of ZA? Please help

Mathematics

1 answer:

ElenaW [278]3 years ago

8 0

If you mean the measure of angle A then the answer is 28°

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Pleas help me !!! It’s due today

kolezko [41]

KE=0.5xmxv2
=0.5x 1.2x10^3x (3.4x10^3)^2=6936000000

6 0

3 years ago

paris run 3 1/2 laps around the circular track in the school gym. The track has a diameter of 1/2 mile. About how far does paris

fiasKO [112]

Answer:

5.497787144 miles

Step-by-step explanation:

Remember that circumference of a circle can be calculated with:

$2\pi r$

r=radius

We also know that the radius is just a half of the diameter.

So, the radius of the track is (1/2)/2=1/4 miles

Now, use the circumference of a circle formula to find how much she runs in 1 lap.

$2\pi (\frac{1}{4} )$

Simplify

$\frac{\pi }{2}$

This is how much she runs in 1 lap.

Multiply by 3.5 for 3 and a half laps.

$\frac{\pi }{2}*3.5$

The answer is around 5.497787144 miles.

7 0

3 years ago

Please answer this very simple and easy attachment I will say what each choose is down below! The chooses have 4 options each ex

Bas_tet [7]

Answer:

1st choose: Rounded

2nd Choose: 36

3rd Choose: 6

Step-by-step explanation:

1st Choose: You want rounded numbers because it makes the problem simpler.

2nd Choose: 35 3/4 rounds to 36.

3rd Choose: 5 7/8 rounds to 6. 36 and 6 divides evenly.

Hopes this helps:)

7 0

3 years ago

The first step when dividing 9m2 − 4m − 6 by 3m is shown. Which could be the next step? 3m − − 3m − − 3m − − 3m − −

anygoal [31]

Hi:)
9m²/3m=3m

4m/3m=4/3

6/3m=2/m

3m-4/3-2/m

Hope i helped !!!

6 0

3 years ago

Read 2 more answers

A rectangular box with a square base is to be constructed from material that costs $9 per ft2 for the bottom, $5 per ft2 for the

kramer

Answer:

$18.73ft^3$

Step-by-step explanation:

Let

Side of square base=x

Height of rectangular box=y

Area of square base=Area of top= $(side)^2=x^2$

Area of one side face= $l\times b=xy$

Cost of bottom=$9 per square ft

Cost of top=$5 square ft

Cost of sides=$4 per square ft

Total cost=$204

Volume of rectangular box= $V=lbh=x^2y$

Total cost= $9(x^2)+5x^2+4(4xy)=14x^2+16xy$

$204=14x^2+16xy$

$204-14x^2=16xy$

$y=\frac{204-14x^2}{16x}=\frac{102-7x^2}{8x}$

Substitute the values of y

$V(x)=x^2\times \frac{102-7x^2}{8x}=\frac{1}{8}(102x-7x^3)$

Differentiate w.r.t x

$V'(x)=\frac{1}{8}(102-21x^2)=0$

$V'(x)=0$

$\frac{1}{8}(102-21x^2)=0$

$102-21x^2=0$

$102=21x^2$

$x^2=\frac{102}{21}=4.85$

$x=\sqrt{4.85}=2.2$

It takes positive because side length cannot be negative.

Again differentiate w.r. t x

$V''(x)=\frac{1}{8}(-42x)$

Substitute the value

$V''(2.2)=-\frac{42}{8}(2.2)=-11.55$

Hence, the volume of box is maximum at x=2.2 ft

Substitute the value of x

$y=\frac{102-7(2.2)^2}{8(2.2)}=3.87 ft$

Greatest volume of box= $x^2y=(2.2)^2\times 3.87=18.73 ft^3$

5 0

4 years ago