Vincent propses an idea to the student government to install a basket hoop along with a court marked with all the shooting lines
and boundary lines at his school for students to use at recess.He presents a plan to install a half-court design as shown below. After checking with the school administration he is told it will be approved if it fits on the empty lot that measures 25 feet by 75 feet on the school property
1 answer:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
Scale Drawing Lengths: . . / .
Actual Court Lengths . . .
Scale Factor: inch corresponds to ( ∙ ) inches, or inches, so the scale factor is .
Let = , represent the scale drawing lengths in inches, and represent the actual court lengths in inches. The -values must be converted from feet to inches.
To find actual length:
= =
() = inches, or feet
To find actual width:
= = ( )
= / ∙ /
= inches, or feet
The actual court measures feet by feet. Yes, the lot is big enough for the court Vincent planned. The court will take up the entire width of the lot.
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Answer:
3 metres
Step-by-step explanation:
If we draw this out, we'll see that there are actually two similar right triangles (see attachment), which means that we can set up a proportion.
The height of the lookout tower corresponds to the height of the wooden column, while the shadow of the lookout tower corresponds to the shadow of the wooden column. We can then write:
(height of lookout tower) / (shadow of tower) = (height of column) / (shadow of column)
16 / 12 = 4 / x , where x is the shadow / unknown we want to find
Cross-multiply:
16x = 48
x = 3
The answer is thus 3 metres.
