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nalin [4]
2 years ago
12

Could you possibly figure this out for me​

Mathematics
1 answer:
damaskus [11]2 years ago
8 0

Answer:

88

Step-by-step explanation:

i used 1980 and 1985. I subtracted 42.1 by 33.4, got 8.7, divided that by 5 since theres been 5 years since, then multiplied by 6 since theres a 6 year difference from 2005 and 2011, then added them.

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1-22 teacher was no help
damaskus [11]
1) 1,2,3,4,5,6,7
2) -3,-2,-1,0,1,2,3,4,5,6,7
3)-3,-2,-1
4)1,2,3,4
3 0
3 years ago
To begin solving this system of linear equations by elimination,you can add the equations
oksian1 [2.3K]

Answer:

The Correct option is C. Addition Property of Equality.

For above Equation by Elimination we use

Addition Property of equality

Step-by-step explanation:

Given:

Addition Property of Equality :

The property that states that if you add the same number to both sides of an equation, the sides remain equal (i.e., the equation continues to be true.)

Here equation is given as

     3x   +   4y   =   38

  + 5x   -   4y    =   -30

-------------------------------------

                 8x    =   8

------------------------------------

Here +4y and -4y gets cancelled or becomes 0 hence 8x = 8.

For above Equation by Elimination we use

Addition Property of equality

5 0
3 years ago
Find the value of x in each of the following
skelet666 [1.2K]
A) 2x-7=13
2x=20
x=10

B) 3x+4=25
3x=21
x=7
6 0
3 years ago
.
KIM [24]

Answer:

x=-1 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

3 0
2 years ago
A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip
DochEvi [55]

Answer:

The expression that represents the population of elk is: \text{elk}(t) = 2*3^t. It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at \text{elk}(0) = 2, then after the first year the population will be:

\text{elk}(1) = \text{elk}(0)*3 = 2*3

While on the second year, it'll be:

\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2

On the third year:

\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3

And so on, therefore the expression that describes the population of elk as the years passes is:

\text{elk}(t) = 2*3^t

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6

The population will reach 1,458 elk in 6 years.

8 0
3 years ago
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