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polet [3.4K]
3 years ago
11

Movie executives want to know if a movie watcher’s heart rate increases when they watch certain types of movies. Subjects in t

he experiment were given a free movie ticket and randomly assigned to watch one of four movies: an action-adventure film, a horror film, a romantic comedy, or an animated children’s film. They measured the average heart rate of all subjects while watching the assigned film.
Which of the following is the most appropriate statistical test to use to test if the average heart rate of the movie watchers was different for the four types of movies?

A. Matched pairs t-test

B. Chi-squared test for independence

C. ANOVA

D. Two-sample t-test

E. Inference for regression
Mathematics
1 answer:
Sedbober [7]3 years ago
5 0

Answer:

The correct option is C

Step-by-step explanation:

ANOVA is the correct option because it can be used to carry out comparison of average of more than  two groups  

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A father's age is three times the age of his son. If sum of their ages is 48, what is the age of son
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2 years ago
Find the area of the trapezoid.<br> b1=5<br> b2=7<br> h=4<br><br> PLEASE EXPLAIN TOO!
olga_2 [115]

Step-by-step explanation:

The formula for finding the area of a trapezoid is\frac{b_{1} + b_{2} }{2} ×h

Start by substituting the values given in the problem into the formula

\frac{5+7}{2} ×4

Now Simply/solve

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4 0
2 years ago
Read 2 more answers
A) Model this situation with a linear system:
sergejj [24]

Answer:

The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

Step-by-step explanation:

Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:

286 = 6 days and 320 km

320/6 = 53,333 km

286/6 = $ 47,666

Thus, the value of 1 day and 53,333 km is $ 47,666.

605 = 10 days and 900 km

900/10 = 90 km

605/10 = $ 60.5

Thus, the value of 1 day and 90 km is $ 60.5.

90 - 53,333 = 36,666

60.5 - 47.666 = 12.833

12,833 / 36,666 = value per kilometer traveled

0.35 = value per kilometer traveled

(286 - (0.35 x 320)) / 6 = X

(286/112) / 6 = X

174/6 = X

29 = X

(605 - (0.35 x 900)) / 10 = X

(605 - 315) / 10 = X

290/10 = X

29 = X

Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

3 0
3 years ago
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