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rjkz [21]
3 years ago
8

What is the volume of the square pyramid with base edges 10 in. and height 9 in.?

Mathematics
1 answer:
klemol [59]3 years ago
5 0
The answer is 300.

Hope this helps!
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Hannah is saving money for a car. She earns $160 each week working part time after school and on the weekends at Papa's Pizza. H
Yuliya22 [10]
From the problem we know that Hanna saves one-half of her paycheck each week, so she saves ( \frac{1}{2})(160)= \frac{160}{2} =80. Also, we know that her parents put $50 in her savings account each week, so the total amount she and her parents put in her saving's account is 80+50=130.
Since we know that Hanna currently has <span>$1,280 in her saving's account and each week she and her parents deposit $130 to the account, with </span>n representing the number of weeks, we can model the situation as follows:
f(n)=1280+130n
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Solve for x:<br>1 73x + ​
Westkost [7]

Answer: This is an incomplete question...

Step-by-step explanation:

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3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The
TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

= \frac{3}{8} = 0.375

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

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3 years ago
Figure out this 16r^3t^2/-4rt
ElenaW [278]
You mean to simplify as this is an expression not an equation, as it has no equal sign...

Factor our 4 first

(4r^3t^2)/(-rt)

Now factor out -rt

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Answer:

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Step-by-step explanation:

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