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shusha [124]
3 years ago
12

Can someone please help??? WILL MARK BRAINLIEST

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
8 0

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)


To find the slope, you can use the slope formula and plug in the two points:

(3,63) = (x₁ , y₁)

(5,107) = (x₂, y₂)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{107-63}{5-3}

m=\frac{44}{2}

m = 22


Now that you know m = 22, plug it into the equation:

y = mx + b

y = 22x + b

To find "b", plug in one of the points into the equation (I will do both points)

(3,63)

y = 22x + b

63 = 22(3) + b

63 = 66 + b    Subtract 66 on both sides

-3 = b


(5,107)

y = 22x + b

107 = 22(5) + b

107 = 110 + b    Subtract 110 on both sides

-3 = b


y = 22x - 3

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I hope this helps you

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3 years ago
An apartment building produces $4,000 per quarter in gross rents. The maintenance expenses run $350 per month. Property taxes ar
S_A_V [24]

Answer:

0.16%

Step-by-step explanation:

Cost of rent per quarter = $4000

Cost of rent per year = 4×$4000

= $16,000

This means that the apartment building produces $12,000 per year in gross rents.

Yearly Expenses are as follows;

Maintenance expenses per year = 12×$350 = $4200

Property taxes per year = $1,750

Mortgage payment per year = 12×$650 = $7800

Total expenses per year = sum of all the yearly expenses

= $4200+$1,750+$7800

= $13750

Yearly revenue generated = Cost of rent per year - total yearly expenses

= $16,000-$13750

= $2250 (net operating income)

Capitalization rate is given as the ratio of the net operating income to the market value of the building.

Capitalization rate = net operating income/market value of building

Since the building with $83750, that will be its market value

Cap rate = $13750/$83750

Cap rate = 0.16%

5 0
3 years ago
Alice weighs 20 dogs and 20 cats. The mean weight for the dogs is 32kg and the mean weight for cats is 4kg. The range in weight
azamat

With the mean and range, we can estimate the weights of the smallest and largest animals in each group.

For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]

<h3>Which conclusions can be made with the given information?</h3>

We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.

  • From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
  • And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg

(Assuming a normal distribution).

Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:

  • The largest dog weights 32kg + 45kg/2 = 54.5kg
  • The smallest dog weights 32kg - 45kg/2 = 9.5kg

(again, assuming a normal distribution).

If you want to learn more about means and ranges:

brainly.com/question/14532771

#SPJ1

3 0
2 years ago
Please help! Solve for x.5x+10=2x-11
earnstyle [38]
Your solution is x= -7
5x+10=2x-11
(5x-2x)+10=(2x-2x)-11
3x+10=-11
3x(+10-10)=(-11-10)
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6 0
3 years ago
Read 2 more answers
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The answer is 7/25, because cos is opposite/hypothenuse.

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