Answer:
the answer is no
Explanation:
I don't no
Breaker A
Because the temperature is cooler in A then the rest
A
14=pH + pOH
pOH= 14 - 2
pOH= 12
pOH= -log[OH]
[OH]= 10^-12
=1×10^-12
Solution A is correct.
Strong acids or bases are assumed to dissociate completely when in a aqueous solution.
