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2 years ago

As the atoms of the elements from atomic

Chemistry

1 answer:

In-s [12.5K]2 years ago

7 0

Answer:

smaller, greater

Explanation:

Moving from left to right in the periodic table, we notice that the magnitude of nuclear charge increases with increasing atomic number.

Recall that across the period, nuclear charge increases without a corresponding increase in the number of shells hence the size of the atom (atomic radius) contracts due to a greater pull of the nuclear charge on the electrons.

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The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga

Rashid [163]

Answer:

Final temperature of the gas is 576 $^{0}\textrm{C}$ .

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

where $V_{1}$ and $V_{2}$ are volume of gas at $T_{1}$ and $T_{2}$ temperature (in kelvin scale) respectively.

Here $V_{1}=158mL$ , $T_{1}=(273+25)K=298K$ and $V_{2}=450mL$

So $T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K$

849 K = (849-273) $^{0}\textrm{C}$ = 576 $^{0}\textrm{C}$

So final temperature of the gas is 576 $^{0}\textrm{C}$ .

3 0

3 years ago

Which equations are in standard form? Check all that apply

aliya0001 [1]

Answer:

2x+3y=-6

4x+3y=12

3x-y=5

5x+3y=1

Explanation:

standard form: ax + by = C

4 0

3 years ago

The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9

emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

5 0

3 years ago

Which of the following elements is a metalloid?

Deffense [45]

The answer to your question would be silicon. I hope this helped!!!

4 0

3 years ago

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How much work is required to pull a sled if you use 60J of work in 5 seconds?

Natali [406]

Answer:

DO I Look Like santa too you how am i supposed to know How about this how about you goo.gle the answer wow smart

Explanation:

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3 years ago