False .........................................
<u>Answer:</u> The nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.
<u>Explanation:</u>
Nuclear reaction are defined as the reactions in which nucleus of an atom is involved.
Positron emission is defined as the emission process in which positron particle is emitted. In this process, a proton gets converted to neutron and an electron neutrino particle.
The chemical equation for the reaction of He-3 with a proton follows:
Hence, the nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.
Answer:
0.00725 M
Explanation:
Considering for
Mass = 5.66 g
Molar mass of = 80.043 g/mol
Moles = Mass taken / Molar mass
So,
<u>Moles = 5.66 / 80.043 moles = 0.0707 moles</u>
will dissociate as:
Thus 1 mole of yields 1 mole of ammonium ions. So,
<u>Ammonium ions furnished by = 1 × 0.0707 moles = 0.0707 moles</u>
Considering for
Mass = 4.42 g
Molar mass of = 149.09 g/mol
Moles = Mass taken / Molar mass
So,
Moles = 4.42 / 149.09 moles = 0.0296 moles
will dissociate as:
Thus 1 mole of yields 3 moles of ammonium ions. So,
<u>Ammonium ions furnished by = 3 × 0.0296 moles = 0.0888 moles</u>
<u>Total moles of the ammonium ions = 0.0707 + 0.0888 moles = 0.1595 moles</u>
Given that:
Volume = 22.0 L
So, Molarity of the is:
<u>Molarity = Moles / Volume = 0.1595 / 22 M = 0.00725 M</u>
flagellate forms of the protist Naegleria fowleri
Uh, not sure if you're asking or not, but during beta decay TI-207 emits a beta particle.