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kakasveta [241]
3 years ago
11

The chemical name of copper ii tetra sulphate pentahydrate​

Chemistry
1 answer:
Anastasy [175]3 years ago
3 0

hope it's helpful ❤❤❤

THANK YOU.

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At 20.°C, a 1.2-gram sample of Mg ribbon reacts rapidly with 10.0 milliliters of 1.0 M HCl(aq). Which change in conditions would
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Answer: (2) decreasing the concentration of HCl(aq) to 0.1 M

Explanation: Rate of a reaction depends on following factors:

1. Size of the solute particles: If the reactant molecules are present in smaller size, surface of particles and decreasing the size increases the surface area of the solute particles. Hence, increasing the rate of a reaction.  

2. Reactant concentration: The rate of the reaction is directly proportional to the concentration of reactants.

3. Temperature: Increasing the temperature increases the energy of the molecules and thus more molecules can react to give products and rate increases.

(1) Increasing the initial temperature to 25°C will increase the reaction rate.

(2) Decreasing the concentration of HCl(aq) to 0.1 M will decrease the reaction rate due to lesser concentration.

(3) Using 1.2 g of powdered Mg will increase the reaction rate due to large surface area.

(4) Using 2.4 g of Mg ribbon will increase the reaction rate due to high concentration of reactants.

7 0
3 years ago
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Answer choices are A. Constant speed<br> B. Stopped<br> C.Moving sideways<br> D.Accelerating
Maurinko [17]
B.stopped
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7 0
3 years ago
Which of these measurements is expressed as three significant figures?
kipiarov [429]

Which of these measurements is expressed as three significant figures?  


C. 4.20 g


6 0
3 years ago
Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in
Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is  2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\   \frac{m_{S} }{m_{O} }= 2

Let us express it as

SO_{\frac{m_{S} }{m_{O} }} = 2

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\   \frac{m_{S} }{m_{O} }= 1

Let us express it as

SO_2_{\frac{m_{S} }{m_{O} }}= 1

Now, for the ratio of both the above-calculated ratios,

\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}

The required ratio is 2:1

3 0
3 years ago
Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachlori
mario62 [17]

Answer:

0.55mL of carbon tetrachloride

Explanation:

CH4(g) + 2Cl2(g) -------> CCl4(g) + 2H2(g)

From the balanced reaction equation

44800mL of chlorine produces 22400 ml of carbon tetrachloride

If 1.1mL of chlorine were consumed, volume of carbon tetrachloride= 1.1×22400/44800

=0.55mL of carbon tetrachloride

Note: 1 mole of a gas occupies 22.4L volume or 22400mL

7 0
3 years ago
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