Answer: 0.600 moles
Balanced eqn for decomposition of the rocket fuel:
2 NH4ClO4 (s) ----> N2 (g) + Cl2 (g) + 2 O2 (g) + 4 H2O (g)
Since, 2 moles of NH4ClO4 produces 2 moles of O2 gas, this means that 0.6 moles of NH4ClO4 will produce 0.6 moles of O2 gas
H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)
2H⁺ + SO₄²⁻ + 2Na⁺ + 2OH⁻ → 2Na⁺ + SO₄²⁻ + 2H₂O
H⁺ + OH⁻ → H₂O (the net ionic equation)
Answer:
Explanation:
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In this case, given the volume (1cm³=1mL) and density of the bromine we are to firstly compute the mass since it will allow us to compute the representative particles:
Next, since the mass of one mole of diatomic bromine is 159.82 g (one bromine weights 78.91), we can next compute the moles in that sample:
Finally, via the Avogadro's number we can compute the representative particles of bromine as follows:
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To calculate the atomic mass of an element, the atomic masses of their isotopes must be considered. Their abundances must also be taken into account. This is the formula used for the calculation:
avg. atomic mass= ∑ <span>(isotope × abundance).
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