N2 + 3 H2 → 2 NH3

In a laboratory preparation room one may find a reagent bottle containing 5.0 L of 12 M NaOH. Write a set of instructions for th

kari74 [83]

Answer: The volume taken from the reagent bottle must be 72.91 mL

Explanation:

To calculate the volume of concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution which is the reagent bottle.

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution which is the solution to be prepared.

We are given:

$M_1=12M\\V_1=?mL\\M_2=3.5M\\V_2=250mL$

Putting values in above equation, we get:

$12\times V_1=3.5\times 250\\\\V_1=72.91mL$

Hence, the volume taken from the reagent bottle must be 72.91 mL

3 0

3 years ago

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct

Nadya [2.5K]

XY4Z2-->Square planar (Electron domain geometry: Octahedral) sp3d2
XY4Z-->Seesaw (Electron domain geometry: Trigonal bipyramidal) sp3d
XY5Z-->Square pyramidal (Electron domain geometry: Octahedral) sp3d2
XY2Z3-->Linear (Electron domain geometry: Trigonal bipyramidal) sp3d
XY2Z-->Bent (Electron domain geometry: Trigonal planar) sp2
XY3Z-->Trigonal pyramidal (Electron domain geometry: Tetrahedral) sp3
XY2Z2-->Linear (Electron domain geometry: Tetrahedral) sp3
XY3Z2-->T shaped (Electron domain geometry: Trigonal bipryamidal) sp3d
XY2-->Linear (Electron domain geometry: Linear) sp
XY3 Trigonal planar (Electron geometry: Trigonal planar) sp2
XY4-->Tetrahedral (Electron domain geometry: tetrahedral) sp3
XY5-->Trigonal bipyramidal (Electron domain geometry: Trigonal bipyramidal) sp3d
XY6-->Octahedral (Electron domain geometry: Octahedral) sp3d2

7 0

3 years ago

Read 2 more answers

How many electrons are in a s-2 ion

Zielflug [23.3K]

Answer:

the ion will have additional 2 electrons so it will be 18

6 0

2 years ago

Which description identifies the correct charge of each atomic particle? A. electron = positive; proton = negative; neutron = no

stiv31 [10]

B. electron = negative; proton = positive; neutron = no charge

3 0

3 years ago

A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak

baherus [9]

Answer:

The volume of the sample is 17.4L

Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

0.1800mol + 0.1800mol reactants =

0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.

Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:

V1n2 = V2n1

Where V is volume and n moles of 1, initial state and 2, final state of the gas

Replacing:

V1 = 23.2L

n2 = 0.2700 moles

V2 = ??

n1 = 0.3600 moles

23.2L*0.2700mol = V2*0.3600moles

17.4L = V2

<h3>The volume of the sample is 17.4L</h3>

8 0

2 years ago