Question

The optimal height h of the letters of a message printed on pavement is given by the formula %20%3D%20%5Cfrac%7B0.00252%20d%5E%7B2.27%7D%7D%7Be%7D" id="TexFormula1" title="h = \frac{0.00252 d^{2.27}}{e}" alt="h = \frac{0.00252 d^{2.27}}{e}" align="absmiddle" class="latex-formula">. Here d is the distance of the driver from the letters and e is the height of the​ driver's eye above the pavement. All of the distances are in meters. Find h for the given values of d and e.
d = 92.4 m, e = 1.7 m.

Answer 1

Answer:

The value of h is 42.956 approximately.

Step-by-step explanation:

Consider the provided formula $h=\dfrac{0.00252 d^{2.27}}{e}.$

Here d is the distance of the driver from the letters and e is the height of the​ driver's eye above the pavement. All of the distances are in meters.

We need to find the value of h where the value of d = 92.4 m, e = 1.7 m.

Substitute d = 92.4 m, e = 1.7 m in above formula and solve for h.

$h=\dfrac{0.00252\left(92.4\right)^{2.27}}{1.7}$

$h\approx\dfrac{0.00252\left(28978.4648\right)}{1.7}$

$h\approx\dfrac{73.0257}{1.7}$

$h\approx42.956$

Hence, the value of h is 42.956 approximately.