let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.
![\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20sin%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B5%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B6%7D%7D%5Cqquad%20%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Badjacent%20side%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Cpm%5Csqrt%7Bc%5E2-b%5E2%7D%3Da%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cpm%5Csqrt%7B6%5E2-5%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B36-25%7D%5Cimplies%20%5Cpm%20%5Csqrt%7B11%7D%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
<em>Hello, I think the answer is -0.84 Hope That Helps!</em>
Answer:
Number of games won = 110
Step-by-step explanation:
Given:
Total games played = 154
The ratio of number of games won to number of games lost = 
Solution:
Let the number of games won be = 
Thus, number of games lost = 
The total games played can be given as = 
Thus, we have:
Dividing both sides by 7.
∴ 
So, number of games won = 
Step-by-step explanation:
False
Answers:
1) The constant of the polynomial expression represents the:
number of group members when the site launches
2) The binomial (1+7x) is a factor of the polynomial expression and represents the:
number of members per group after x months
Solution:
1) The estimate for the total number of groups members (y) is given by the polynomial expression:
y=14x^2+37x+5
where x is the number of months since the site's launch.
When the site launchs:
x=0→y=14(0)^2+37(0)+5=14(0)+0+5=0+0+5→y=5
The number of group members when the site launches is 5
And the problem says: "The site will launch with five study groups"
2) The site will launch with five study groups, each with its creator as its only member, then the number of members per group is 1.
Richard estimates that seven new members will be added to each study group every month (x), then:
The number of members per group after x months will be: 1+7x
