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gayaneshka [121]
4 years ago
12

G(x) = -10x2+ 490 lesser x= greater x =

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
7 0

Answer:

Greater x =+ 7

Lesser x = -7

Step-by-step explanation:

G(x) = -10x2+ 490

Let the left side = 0

So we have

0= -10x2+ 490

Solving the above now by allowing the variable with the coefficient of x cross the equal sign.

10x²= 490

Dividing by 10

X²= 490/10

X² = 49

Taking the root of both sides

X= √49

X = + 7or -7

Bigger x =+ 7

Smaller x = -7

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Point P lies on circle C, x^2+y^2=36. There are two unique tangents to circle D, x^2+y^2=18 that pass through point p. What is t
Anastasy [175]

Answer:

90°

Step-by-step explanation:

Circle C has radius √36 = 6

Circle D has radius √18 = 3√2

As the D radius intersecting either point of tangency, does so at a right angle.

The half angle θ between the tangents is

sinθ = 3√2 / 6 = ½√2

θ = 45°

so the angle between the tangents is 2(45) = 90°

6 0
3 years ago
How to get the answer to this equation 1+4=5 2+5=12 3+6=21 8+11=?
const2013 [10]
The answer is 40. 1+4=5, 5+2+5=12, 12+3+6=21, 21 +8+11=40
6 0
3 years ago
Slope = -1/6; (12,-2)
stira [4]

Equation is y = -1/6x

Step-by-step explanation:

  • Step 1: Given that slope, m = -1/6 and a coordinate (12,-2). Write the equation and find the y-intercept, b.

⇒ y = mx + b

⇒ -2 = -1/6 × 12 + b

⇒ -2 = -2 + b

∴ b = 0

  • Step 2: Write the equation in slope intercept form.

⇒ y = -1/6x + 0

⇒ y = -1/6x

4 0
3 years ago
PLEASE HELP ME OUT (geometry)
jekas [21]

Answer:

x =60 ° angles on a straight line

y+25° =120° exterior angle of the triangle

y=120°-25°=95°

y =95 °

4 0
3 years ago
A circle has a radius of (6x+11) centimeters. Which statement is true?
PolarNik [594]

If a circle has a radius of (6x + 11), it is true that: <u>D. The </u><u>circumference </u><u>of the </u><u>circle </u><u>is </u>(12x + 22) \pi $ cm<u />

<em><u>Recall the following about a </u></em><em><u>circle</u></em><em><u>:</u></em>

  • Area of a circle = \pi r^2
  • Circumference of a circle = 2 \pi r

If a circle has a radius of (6x+11) $ cm, the area and circumference of the circle would be the following:

  • Area of a circle =  \pi r^2

  • Substitute  r = (6x+11) into the area formula

\pi (6x + 11)^2

  • Expand

\pi \times (6x + 11) \times (6x + 11)\\\\\pi \times(36x^2 + 66x + 66x + 121)\\\\\pi \times  (36x^2 + 132x + 121)\\\\ area = (36x^2 + 132x + 121) \pi $ cm^2

  • Circumference of a circle = 2 \pi r

  • Substitute  r = (6x+11) into the circumference formula

2 \times \pi \times  (6x + 11)\\\\Circumference = (12x + 22) \pi

Therefore, if a circle has a radius of (6x + 11), it is true that: <u>D. The </u><u>circumference </u><u>of the </u><u>circle </u><u>is </u>(12x + 22) \pi $ cm<u />

Learn more here:

brainly.com/question/14772815

6 0
3 years ago
Read 2 more answers
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