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Sonja [21]
3 years ago
15

96:120 simply To the least

Mathematics
1 answer:
lidiya [134]3 years ago
7 0

Answer:

4:5

Step-by-step explanation:

96:120

simplified:

divide both sides of colon by 24:

4:5

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a rectangle's length is three more than two times its width if the perimeter of a rectangle is 66 ft what is the measurement of
Lemur [1.5K]

Answer:

The measure of the length is 23\ ft

Step-by-step explanation:

Let

x-----> the length of rectangle

y-----> the width of rectangle

we know that

The perimeter of rectangle is equal to

P=2(x+y)

P=66\ ft

so

66=2(x+y)

Simplify

33=x+y -----> equation A

x=2y+3 ----> equation B

Substitute equation B in equation A and solve for y

33=(2y+3)+y

2y+y=33-3

3y=30

y=10\ ft

Find the value of x

x=2(10)+3=23\ ft

8 0
3 years ago
Read 2 more answers
Describe how to solve d = rt for t
kotegsom [21]

Answer:

t = d/r

Step-by-step explanation:

Given the equation, d = rt for <em>t</em><em>:</em>

Switch sides:

rt = d

Divide both sides by r to isolate<em> t</em>:<em>  </em>

\frac{rt}{r} =  \frac{d}{r}

t = d/r

6 0
2 years ago
Please answer I’ll pay you $100 lol thanks
Nesterboy [21]

Answer:

d = \pi

e = -\sqrt{8}

f = \frac{3}{2}

Step-by-step explanation:

D is equal to pi because pi is 3.1415... Therefore we need a point that is a little more than -3 and that is point d.

-\sqrt{8} is roughly equal to -2.8 because 3 * 3 = 9 so that is too much, and 2 * 2 = 4 is too little so it has to be between -2 and -3. Therefore the point is e.

For 3/2 it has to be less than 2 because 2 cannot go into 3 more than once. The point would then be point f.

<em>Hope this helps!!</em>

<em>- Kay :)</em>

4 0
3 years ago
Find an equation of the plane that passes through the point P0(- 3,3,1) with a normal vector n = (1,4, -3). Which of the followi
Flura [38]

Take an arbitrary vector (<em>x</em>, <em>y</em>, <em>z</em>), which goes from the origin to some point (<em>x</em>, <em>y</em>, <em>z</em>) on the plane we want to find.

Subtract from this vector, the vector that points to P_0, which is (-3, 3, 1). This translates the first vector so that it starts at the point P_0 and is directed at some point (<em>x</em>, <em>y</em>, <em>z</em>). We get a new translated vector, (<em>x</em> + 3, <em>y</em> - 3, <em>z</em> - 1), which lies in the plane.

The normal vector to the plane is orthogonal to every vector in the plane. So taking the dot product of any vector in the plane with the normal to the plane will always result in 0. We use this to find the plane's equation:

\vec n\cdot((x,y,z)-P_0)=(1,4,-3)\cdot(x+3,y-3,z-1)=0

\implies(x+3)+4(y-3)-3(z-1)=0

\implies x+4y-3z=6

and so the answer is D.

6 0
3 years ago
If T(n) =3x+2 find the value of y when x=-2
Troyanec [42]
Replace the x in 3x + 2 by -2 and calculate:-

y = 3(-2) + 2
= -6 + 2
= -4 answer

3 0
3 years ago
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