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Fynjy0 [20]
3 years ago
12

What is the domain and range for the following relation.

Mathematics
1 answer:
8090 [49]3 years ago
3 0

Answer:

the domain is the set of all x coordinations and the range is the set of all y coordinates. therefore, the answer is C.

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I really need help with my take home test. The problem is f(x)=(x-7)/2, what is the value of (f°f^-1)(3). Really struggled with
kiruha [24]
Answer: 3) 3
First,We can find the inverse function of f(x) which is f^-1(x);
Let f(x)=y , x=f^-1(y)
(x-7)/2=y
(x-7)=2y
x=2y+7
Subtitute this equation x=2y+7 in the equation f^-1(y) and we have;
f^-1(y)=2y+7
change y into x,
f^-1(x)=2x+7

(f°f^-1)(3)=(f×(f^-1)(3))
=f(2×(3)+7)
=f(6+7)
=f(13)
=(13-7)/2
=6/2
=3
Hope this helps and sorry if my answer is wrong.
5 0
3 years ago
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Akimi4 [234]

Answer:

- m - 6n + 10

Step-by-step explanation:

-(m + 6n - 10)

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v

- m - 6n + 10

5 0
3 years ago
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Factor out the coefficient of the variable 3f 5
algol13
<span>3f5 </span>Changes made to your input should not affect the solution:

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5 0
4 years ago
Help me with this plsssss
DedPeter [7]

Answer:

Coordinates are ( 1,3 )  x=1    y=3

7 0
3 years ago
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What is the value of x?
jok3333 [9.3K]

Answer:

Solution given:

sin 47=opposite/hypotenuse

Sin 47=x/18

x=sin47*18

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6 0
3 years ago
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