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Fynjy0 [20]
3 years ago
12

What is the domain and range for the following relation.

Mathematics
1 answer:
8090 [49]3 years ago
3 0

Answer:

the domain is the set of all x coordinations and the range is the set of all y coordinates. therefore, the answer is C.

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A coach divided his team into two groups of equal size.
DerKrebs [107]

Applying the percentages, and considering that 70% of the first group drinks at least 2 glasses of water a day, it is found that 0.725 = 72.5% of the team drinks at least 2 glasses of water a day.

The team is divided into two equal groups, hence, each represents 50%.

The <em>percentages </em>associated with drinking at least 2 glasses of water a day is:

  • 70% of 50%(first group)
  • 75% of 50%(second group)

Hence, applying the weighed percentage, the total percentage is:

T = 0.7(0.5) + 0.75(0.5) = 0.725

0.725 = 72.5% of the team drinks at least 2 glasses of water a day.

A similar problem is given at brainly.com/question/1517088

4 0
3 years ago
Laura invests $2,000 in a bank account which pays a compound interest rate of 6.4%. To the nearest cent, what amount is in the a
EastWind [94]

Answer:

9,000

Step-by-step explanation:

it you count with time by ×it would be 9,000 because just add that up with money

7 0
3 years ago
Read 2 more answers
May I get help on these questions, please?
Virty [35]
Hello! here are the basic rules that you need to know to solve these problems:

a diameter is 2 × the radius
the circumference rule is 2×π×radius

I will solve the first question to show how to format.

1: 5/2=2.5
2×2.5×π=5×π=15.7
5 0
2 years ago
What is another way to write 56
SashulF [63]

Answer:

\frac{112}{2}

Step-by-step explanation:

Another way to express 56 is \frac{112}{2} because they are equal values.

3 0
3 years ago
Read 2 more answers
X+3&lt;8 and 3(x+4)-11&lt;10
kondaur [170]

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

4 0
4 years ago
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