Answer:
1 plane
Step-by-step explanation:
Let's suppose the number of planes waiting or on the runway " P "
the number of planes taking off per hour ' 
'
the time for waiting and the runway 
so:
P = x
= 18 airplanes per hour
we know that 1 min = 60s
36s = 36/60 = 0.6 min
Also, 3 min and 30 s = 3 + 30/60 = 3.5 min
Next to find the time for waiting and the runway
∴= 0.6 + 3.5 = 4.1 min/60 (converting into hour)
= 0.068 hour
P = 18x0.068 = 1.23
therefore, there is 1 plane either on the runway or waiting to take off
So, there is 1 plane either on the runway or waiting to take off
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Answer:
v = 25.98
Step-by-step explanation:
You could do this a number of ways. Some are much longer than others. The shortest way is to use the tangent.
Formula
Tan(theta) = opposite / adjacent
Givens
Theta = 30o
Opposite = 15 km
Adjacent = x
Solution
tan(30) = 15 / v Multiply both sides by v
v*tan(30) = 15 Divide by tan(30)
v = 15/tan(30)
tan(30) = 0.5774
v = 15 / 0.5774
v = 25.98
6 x 89 is 534
6 x (90 - 1) is 534. BUT you have to subtract 90 from 1 and that's 89. So then you multiply 6 by 89.
6 x 90 is 540 and 6 x 1 is 6. you take 540 subtract 6 and that's 534.
540 - 6 is 534.
A. true because you got to know where you line is going though
