Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
The equation would be 1.65 + y - 0.15 + 0.45 = ? If you combine like terms you get B) 1.95 y as your answer. I hope this helps!
Answer:
$10.75 x 3 1/2 = $37.625 (rounded to the nearest cent: $37.63). $10.75 x 5 = $53.75. $37.625 + $53.75 = $91.375. (rounded to the nearest cent: $91.38) hope this helps
Step-by-step explanation:
- Zombie
1st you need to fine the slope using
S = y2-y1/x2-x1
S = -6 - 3/2-2
S = -9/0
S = Undefined
when we have undefined slope the equation would be a vertical lines.
Thus the equation would be the x value of the point
Thus the equation is x = 2
(10,6) Down ten and over 6.
