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2 years ago

S = { x ; x is a multiple of 8. 0 < x <30 } Describe this set in another method

Mathematics

1 answer:

Firdavs [7]2 years ago

3 0

Step-by-step explanation:

Hi,

Let's describe it in listing method;

S= {8,16,24}.

Hope you got it...

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irina [24]

5. D
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3 years ago

3 museums charge an entrance fee based on the number of visitors in the group. the tables list the fees charged by the museums.

miv72 [106K]

Museum C because for every 3 guests you pay $4(?) each.

3/4
12/16=3/4
18/24=3/4

6 0

3 years ago

Read 2 more answers

A company tests the life of its rechargeable batteries over six months of use. They test how long a battery will last after a fu

jonny [76]

Answer:

18.6 months

Step-by-step explanation:

Given that :

Best fit line from scatterplot :

y=-12.05x +224.26

x = Number of month

y = charge on battery

Number of months a typical battery uses before being dead completely :

When battery is dead completely ; charge =0, y = 0

y = -12.05x + 224.26

0 = - 12.05x + 224.26

12.05x = 224.26

x = 224.26 / 12.05

x = 18.610788

Hence, 18.6 months before battery is completely dead.

4 0

2 years ago

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

6 0

3 years ago

You have a normal distribution of hours per week that music students practice. The mean of the values is 8 and the standard devi

Alona [7]

Answer:

38%

Step-by-step explanation:

Given that X,the hours per week the music student practice follow a normal distribution.

X:N(8,4)

We have to find the percentage of students who practice between 6 and 10 hours.

6<x<10 implies converting to z

We know z = (x-mean)/sigma = (x-8)/4

Hence 6<x<10 is equivalent to (6-8/4)<Z<(10-8/4)

= |z|<0.5

From std normal table we find this area equals = 0.1915+0.1915

=0.3830 = 0.38 (rounded off)

Hence required percentage = 0.38x100 = 38%

5 0

2 years ago

S = { x ; x is a multiple of 8. 0 < x <30 } Describe this set in another method​

S = { x ; x is a multiple of 8. 0 < x <30 } Describe this set in another method