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3 years ago

The elevation of a sunken treasure is -180 feet. Your elevation is 3/4 of the ship's elevation Whats your elevation?

Mathematics

2 answers:

ss7ja [257]3 years ago

4 0

-135 or positive 135 im not totally sure

stira [4]3 years ago

4 0

( $\frac{-180}{1}$ )( $\frac{3}{4}$ )

$\frac{-540}{4}$

Your elevation is -135 feet

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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

2 years ago

Daja is packing her backpack for school. Her textbook weighs 1 ¼ pounds. Her notebooks weigh ¼ pound. Her other supplies weigh ¾

Shalnov [3]

Answer:

2 1/4 or 2.25

Step-by-step explanation:

1 1/4 + 1/4 = 1 2/4

1 2/4 + 3/4 = 2 1/4

6 0

2 years ago

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Danielle needs to walk 2.5 miles. If she wants to reach her destination in 30 minutes (1/2hour), how fast does she need to walk?

shepuryov [24]

5 mph to get that answer you use the speed equation
speed(mph)=distance(in miles)/time(in hours)
2.5
------ = 5 mph
.5

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3 years ago

There are 6 diagonals that can be drawn from one vertex of an octagon, true or false.

FinnZ [79.3K]

It's False; an octagon has 8 vertices. When you remove the starting vertex and the two adjacent vertices we're left with 5 possible diagonals

6 0

3 years ago

In triangle ABC, angle = 90 degrees. AC = 7, BC = 12. AB = _______ Measure of angle A = _______ Measure of angle B = _______

Ulleksa [173]

Answer:

AB = 13.89

Measure of angle A = 59.74°

Measure of angle B = 30.26°

Step-by-step explanation:

The given parameters are;

∠C = 90°

AC = 7

BC = 12

Part 1

Hence, the question has the dimensions of the two adjacent sides of the right angle (angle 90°)

From Pythagoras theorem, we have;

A² = B² + C²

Where, A is the opposite side to the right angle, hence;

In the ΔABC,

AB ≡ A

Therefore;

AB² = AC² + BC² = 7² + 12² = 193

∴ AB = √193 = 13.89

Part 2

∠A is the side opposite side BC such that by trigonometric ratios

$tan \angle A = \frac{Opposite \, side \, to \, angle \, A}{Adjacent \, side \, to \, angle \, A} = \frac{BC}{AC} = \frac{12}{7} = 1.714$

∴ ∠A = Arctan(1.714) or tan⁻¹(1.714) = 59.74°

Part 3

∠B is found from knowing that the sum of the angles in a triangle = 180°

∴ ∠A + ∠B + ∠C = 180° which gives

59.74° + 90° + ∠B = 180°

Hence, ∠B = 180° - (59.74° + 90°) = 180° - 149.74° = 30.26°.

7 0

3 years ago

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