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Ksivusya [100]
3 years ago
9

The figure represents the shape of a kitchen floor. What is the area? (round to the nearest hundredth)

Mathematics
2 answers:
Masteriza [31]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Murljashka [212]3 years ago
5 0
We would divide the shape into a rectangle and a trapezium

The rectangle is of length, 24.5 ft and width 10.75 ft

Area =  24.5 * 10.75 = 263.375 square feet.


Trapezium :  Parallel sides are 18.5 ft and 24.5 ft
Height:  12 - 10.75 = 1.25ft

Area of Trapezium = (1/2)*(Sum of Parallel sides)*height

                            = 1/2 * (18.5+24.5)* 1.25
                            = 1/2 * 43* 1.25 = 26.875     

Total Area = Area of Rectangle + Area of Trapezium

               =  263.375 + 26.875   = 290.25

Area = 290.25 ft²     (D)
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ivolga24 [154]
(4p +3)(5p2 + 6) is your answer
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3 years ago
Macy's if offering a sale where you can use two different coupons, Coupon A gives 15%
Juliette [100K]

The ticket price of the item after applying coupon B first and then coupon A is $65.45

Coupons reduce the ticket price of an item.

<u><em>Ticket price</em></u><u><em> after </em></u><u><em>coupon B i</em></u><u><em>s applied </em></u>

An item costs $80. After applying the coupon B which gives, $3 off the price, the cost of the item reduces to $77 ($80 - $3).

The ticket price of the item after coupon B is applied is $77

<em><u>Ticket price </u></em><em><u>after c</u></em><em><u>oupon A </u></em><em><u>is applied </u></em>

The item costs $77 when coupon B is applied. If the discount is 15% off on coupon A, it means that the item costs 85%( 100 - 15%) of its initial price.

Ticket Price of the item = percentage price x price of the item after the first coupon B was applied

85% x $77

0.85 x $77 = $65.45

A similar question was solved here: brainly.com/question/17413216?referrer=searchResults

8 0
2 years ago
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 &lt; Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
3 years ago
My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. When
r-ruslan [8.4K]

Answer:  The answer is 0.25 miles.


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Since I started 5 minutes after than my friend, so we are to find the distance travelled by my friend in 5 minutes.

In 1 hour, i.e., 60 minutes, distance travelled by my friend = 3 miles.

In 1 minute, distance travelled by my friend is

\dfrac{3}{60}=\dfrac{1}{20}~\textup{miles}.

Therefore, distance travelled by my friend in 5 minutes will be

\dfrac{1}{20}\times 5=\dfrac{1}{4}=0.25~\textup{miles}.

Thus, the answer is 0.25 miles.

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Answer:

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Step-by-step explanation:

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