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nydimaria [60]
2 years ago
6

Micah has a loan of $6,720. This loan has a simple interest rate of 3.5% per year. What is the amount of interest that Micah wil

l be charged on this loan at the end three years?
Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

Answer: $20,265

Micah will be charged $20,265 over the course of 3 years

Step-by-step explanation:

6,720 + 3.5% = 6,755

6,775 x 3 = 20,265

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Marina86 [1]
The line of symmetry is 1
4 0
3 years ago
A nurse has an income of $120,000. The income tax the nurse has to pay is 6%. What is the amount of income tax, in dollars and c
sleet_krkn [62]

Answer:

7,200 I believe

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How do you solve this?
solong [7]

It looks like your equations are

7M - 2t = -30

5t - 12M = 115

<u>Solving by substitution</u>

Solve either equation for one variable. For example,

7M - 2t = -30   ⇒   t = (7M + 30)/2

Substitute this into the other equation and solve for M.

5 × (7M + 30)/2 - 12M = 115

5 (7M + 30) - 24M = 230

35M + 150 - 24M = 230

11M = 80

M = 80/11

Now solve for t.

t = (7 × (80/11) + 30)/2

t = (560/11 + 30)/2

t = (890/11)/2

t = 445/11

<u>Solving by elimination</u>

Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,

7M - 2t = -30   ⇒   -10t + 35M = -150 … (multiply by 5)

5t - 12M = 115   ⇒   10t - 24M = 230 … (multiply by 2)

Now combining the equations eliminates the t terms, and

(-10t + 35M) + (10t - 24M) = -150 + 230

11M = 80

M = 80/11

It follows that

7 × (80/11) - 2t = -30

560/11 - 2t = -30

2t = 890/11

t = 445/11

4 0
2 years ago
The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili
Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

\lambda= 4.5

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

a) No accidents occur in one week.

P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111

b) 5 or more accidents occur in a week.

P( x \geq 5) = 1-\displaystyle \sum P(x

c) One accident occurs today.

The mean number of accidents per day is given by

\lambda = \dfrac{4.5}{7} = 0.64

P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747

5 0
3 years ago
Several people are standing in line. Starting at 1 end, Santa is the 3rd person. Starting at the other end, he's the 11th person
OlgaM077 [116]

there are 13 people in line

3 0
2 years ago
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