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cricket20 [7]
4 years ago
14

Question 3(Multiple Choice Worth 1 points)

Mathematics
1 answer:
maxonik [38]4 years ago
6 0

Answer:

g(x)=(x+3)^2 best describes g(x)

Step-by-step explanation:

We are given an equation of graphf(x)=x^2

Rule : When the graph f(x) shifts left by c units . So, resultant graph is f(x+c)

Now we are given that The graph of f(x) = x^2 is shifted 3 units to the left to obtain the graph of g(x).

So, By using rule :

f(x+3)=(x+3)^2

So, g(x)=(x+3)^2

So, Option A is true

Hence g(x)=(x+3)^2 best describes g(x)

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A salesperson receives a 2.5% commission on sales, what commission does the salesperson receive for $8,000 in sales
Tcecarenko [31]
Percentage of commission received by the salesperson = 2.5%
Amount of sales made by the salesperson = $8000
Then
The amount of commission received by the salesperson = (2.5/100) * 8000 dollars
                                                                                             = 2.5 * 80 dollars
                                                                                             = 200 dollars
So the salesperson receives a commission of $200 on the total sales made. I hope the procedure is clear enough for you to understand. You can use this method in future for solving similar problems without requiring any help from outside.
7 0
3 years ago
What is the number that 12 + 8i is divided by to yield the number represented by point A on the complex plane?
RoseWind [281]

Answer:

4

Step-by-step explanation:

edge 2020

4 0
3 years ago
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What us the unit price of 32 ounces of yogurt that cost 4.79$
nadezda [96]
Do you mean the cost per ounce? 
Then that would be $0.1496, or rounded to the nearest cent, 15 cents a ounce.
5 0
4 years ago
Find the area! NEED HELP ASAP!!!!!!!!
allochka39001 [22]

seperate it into a square and right triangle

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area of traignle: (1*2)/2= 1m^2

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4 years ago
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What is the smallest value of n such that an algorithm whose running time is 100n 2 runs faster than an algorithm whose running
Semmy [17]

Answer:

n = 15

Step-by-step explanation:

For inputs of the value of n, the running time for the algorithm A is 100n^2 and that of B is 2^n.

If A is to run faster than B, 100n^2 must be smaller than 2^n.

Let's check from n = 1 to know the value of n that fits

n = 1

100(1)^2 > 2^1

100 > 2

n = 2

100(2)^2 > 2^2

400 > 4

n = 4

100(4)^2 > 2^4

1600 > 16

n = 8

100(8)^2 > 2^8

6400 > 2^8

n = 16

100(16)^2 < 2^16

25600 < 2^16

This implies that between n = 8 and 16, A starts to run faster than B

n = (8+16)/2 = 12

100(12)^2 > 2^12

14400 > 2^12

n = (12+16)/2 = 14

100(14)^2 > 2^14

19600 > 2^14

n = (14+16)/2

n = 15

100(15)^2 < 2^15

22500 < 2^15

At n= 15, A starts running faster than B

8 0
4 years ago
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