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3 years ago

Write a function equation that represents a line that contains the two points (-3, 5) and (2, 10).

Mathematics

1 answer:

Eva8 [605]3 years ago

4 0

Step-by-step explanation:

1. 1st of all calculate the gradient

( - 3, 5) ( 2, 10)

Gradient = (10 - 5) / ( 2--3)

= 1

2. Then find the eq

Y = mx + c

Where m is the gradient

y= 1x + c

Now replace any 2 coordinates from above in the eq.

For ex I'm taking (2, 10)

Y = 1x + c

In the coordinate, x = 2 and y =10

By replacing this in the eq, I will find c

10 = 1(2) + c

2 + c = 10

c = 10 - 2

= 8

So the eq is y = x + 8 ⬅️

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Step-by-step explanation:

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= 28 - 18

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An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a

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Answer:

Probability Mass Function:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

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We are given the following information:

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P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

$P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064$

$P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608$

$P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902$

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3 years ago

The resistance, R of a wire varies directly as the length, l, and inversely as the diameter, d, squared. If R is 1.50ohms when l

tatyana61 [14]

Answer:

resistance is 1.5 ohms (1.5 Ω)

Step-by-step explanation:

R varies directly with l

R varies inversely with $d^2$

We can set-up a proportionality statement as shown below:

$R=k\frac{l}{d^2}$

Now, Given,

R = 1.50

l = 2

d = 1.5

We substitute and find k (the proportionality constant):

$R=k\frac{l}{d^2}\\1.5=k\frac{2}{1.5^2}\\1.5=\frac{2k}{2.25}\\2k=1.5*2.25\\2k=3.375\\k=1.6875$

Now, we will use this value of k to solve the problem.

Given,

l = 8

d = 3

and

k = 1.6875

We find R:

$R=k\frac{l}{d^2}\\R=1.6875\frac{8}{3^2}\\R=\frac{1.6875*8}{9}\\R=1.5$

The resistance is 1.5 ohms (1.5 Ω)

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