Answer:
280/4 = 70 miles per hour. Next, take the unit rate and multiply it by the number of hours you are trying to find. In this case, you are trying to find 6 hours and 30 minutes, but this can also be rewritten as 6.5, since 30 minutes is half an hour. So, in 6.5 hours, the car can go 455 miles
Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
The answer is
13.76 because when u multiply negative times negative it gives u a positive
Answer:
This quadratic equation has 2 solutions.
Step-by-step explanation:
I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.
We can solve this equation by expressing it in the form: ax² + bx + c
x² + 9x= -8
x² + 9x + 8 = 0
Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.
In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.
x² + 9x + 8 = 0
(x + 8)(x + 1) = 0
For this equation to be true (= 0), x can equal -8 OR -1.
Hence, this quadratic equation has 2 solutions.
Answer:
Division can be represented with ÷ as well.
