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3 years ago

7

A ball is thrown with an initial velocity of 32 ft/s from a height of 4.5 feet. It’s height as a function of time is given by th

e equation h(t)=-16t2+32t+4.5. How long will the ball be in the air, and how high does the ball go?

1 answer:

Lana71 [14]3 years ago

6 0

Answer:

the ball will be in the air for possibly 2.5 seconds and it max hieght was 10 ft

Step-by-step explanation:

no clue

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