Question

A ball is thrown with an initial velocity of 32 ft/s from a height of 4.5 feet. It’s height as a function of time is given by the equation h(t)=-16t2+32t+4.5. How long will the ball be in the air, and how high does the ball go?

Answer 1

Answer:

the ball will be in the air for possibly 2.5 seconds and it max hieght was 10 ft

Step-by-step explanation:

no clue