The values are x = 8 and x = -1.
To find the undefined values, we need to know when the denominator is zero.
To do this, we need to factor it and find the value that would make either factor equal to zero.
If factors to: (x - 8)(x + 1)
Therefore, the undefined values would be at 8 and -1.
Answer:
y = -1/5 x + 2
Step-by-step explanation:
y = 5x - 4
m = 5
Slope of perpendicular = -1/5
Equation of perpendicular:
y = mx + b
y = -1/5 x + b
Use point (15, -1) for x and y, and solve for b.
-1 = -1/5(15) + b
-1 = -3 + b
b = 2
Equation of perpendicular:
y = -1/5 x + 2
Didn't get the question quite well...
Answer:
The calculation in step 3 is wrong
Step-by-step explanation:
1) The mean of a dataset is given by the sum of the values of the dataset divided by the number of values.
In this problem, the dataset is
35, 16, 23, 42, 19
And the number of data is
N = 5
So the mean is

So, step 1 is correct.
2)
The absolute deviation of a value in the dataset is the absolute value of its difference from the mean value:

Since here the mean value is

Then for each of the values in this dataset, we have:

So calculations in step 2 are also correct.
3)
The mean absolute deviation is given by the sum of the absolute deviations for each data divided by the number of values in the dataset.
Therefore in this problem, it is:

While the result reported by Dora is 9.5: therefore, this step is not correct.