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aivan3 [116]
3 years ago
13

At the store Brand A potato chips were $11.92 for 4 bags. Brand B potato chips were $17.34 for 6 bags. Which brand has the cheap

er price?
Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

Brand B

Step-by-step explanation:

Divide to get the answers.

Brand A: 4 bags for $11.92

11.92/4 = 2.98

Brand B: 6 bags for $17.34

17.34/6 = 2.89

Once you are done dividing, the answer that you get will be the individual price per bags.

So, the answer is: Brand B has cheaper price.

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A right triangle has a height of 20 cm and a base of 10 cm. What is the area of the triangle? (A = 1/2 bh)
alisha [4.7K]

Answer:

100 because its way too ez

7 0
3 years ago
Read 2 more answers
3x+2y-z=8<br> -3x+4y+5z=-14<br> X-3y+4z=-14
Luda [366]

Answer:

B? I think

Step-by-step explanation:

sorry I really want to help but I dont get what the question is asking

4 0
3 years ago
If r=20.5 and s=34.2 find S Round to the nearest tenth
astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

 \alpha =arctan(\frac{opposite}{adjacent})

Knowing that: you need to find the measure of the angle "S" , r=20.5 (which is the adjacent side) and s=34.2 (which is the opposite side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get that the measure of "S" rounded to the nearest tenth is:

S=arctan(\frac{34.2}{20.5})\\\\S=59.1\°

7 0
3 years ago
Read 2 more answers
What is 7/5 divided by 3/10
Mazyrski [523]

Answer:

\frac{11}{10} or 1\frac{1}{10}

Step-by-step explanation:

\frac{7}{5} ÷\frac{3}{10}

= \frac{(7 * 10) - (3 * 5)}{5 * 10}

= \frac{55}{50}

=\frac{55 / 5}{50 / 5}

= \frac{11}{10} or 1\frac{1}{10}

8 0
3 years ago
In matrix multiplication, such as AB=C, the columns of B form the rows of C. why is this?
Gnesinka [82]
Let's work with 2-by-2 matrices so we're on the same page. The ideas will work for any appropriate matrices.

From the rule of matrix multiplication, we see:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right] = \left[\begin{array}{cc} a_{11}b_{11} + a_{12}b_{21} & a_{11}b_{12} + a_{12}b_{22} \\ a_{21}b_{11} + a_{22}b_{21} & a_{21}b_{12} + a_{22} b_{22} \end{array}\right]
As you noted, we see the columns of B contributing to the rows of C. The question is, why would we ever have defined matrix multiplication this way?

Here's a nontraditional way of feeling this connection. We can define matrix multiplication as "adding multiplication tables." A multiplication table is made by starting with a column and a row. For example,
\begin{array}{ccc} {} & 1 & 2 \\ 1 & {} & {} \\ 2 & {} & {} \end{array}
We then fill this table in by multiplying the row and column entries:
\begin{array}{ccc} {} & [1] & [2] \\ 1| &1 & 2 \\ 2| & 2 &4 \end{array}
It's then reasonable to say that given two matrices A and B, we can construct multiplication tables by taking the columns of A and pairing them with the rows of B:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right]

= \begin{array}{cc} {} & \left[\begin{array}{cc} b_{11} & b_{12}\end{array} \right]\\ \left[\begin{array}{c} a_{11} \\ a_{21} \end{array} \right] \end{array} +\begin{array}{cc} {} & \left[\begin{array}{cc} b_{21} & b_{22}\end{array} \right]\\ \left[\begin{array}{c} a_{12} \\ a_{22} \end{array} \right] \end{array}

= \left[\begin{array}{cc} a_{11} b_{11} & a_{11} b_{12} \\ a_{21} b_{11} & a_{21} b_{12} \end{array} \right] + \left[\begin{array}{cc} a_{12} b_{21} & a_{12} b_{22} \\ a_{22} b_{21} & a_{22} b_{22} \end{array} \right]

Adding these matrices together, we get the exact same expression as the traditional definition. 




5 0
3 years ago
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