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3 years ago

Please help me solve this math it’s due in 1 hour

Mathematics

1 answer:

german3 years ago

4 0

If you count over left you get 7.5. Then count right thrashed amount & you get 15.
15 yard line would be the answer.

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Find the sixth term of the geometric sequence when a4=−8 and r=0.5

grandymaker [24]

Answer:

Step-by-step explanation:

to find a term in the sequence multiply the previous term by r , then

a₄ = - 8 , so

a₅ = - 8 × 0.5 = - 4

a₆ = - 4 × 0.5 = - 2

4 0

2 years ago

Jace and Ellie are helping their friend Oliver move: Jace can move one box for every two boxes does Elle can move five boxes how

Simora [160]

Answer:

Two.

Step-by-step explanation:

If Ellie moves five boxes, and Jace can move one for every two Ellie moves, Jace can move two boxes.

3 0

2 years ago

What is 101,949 rounded to the nearest hundred thousand?

kobusy [5.1K]

Well the answer is 103,000 because when you round it the 1 becomes a 2

5 0

3 years ago

Read 2 more answers

6. Steve is packing sacks for treats at a party. Every sack is exactly the same. Steve has 42 candy bars and 126 lollipops. a. W

Sergeu [11.5K]

Answer:

Greatest sack = 42

1 candy bar and 3 lollipops

Step-by-step explanation:

Represent Candy bars with C and Lollipops with L

$C = 42$

$L= 126$

Solving (a): Greatest number of treat sacks

To solve this, we simply calculate the GCF of C and L

$42 = 2^1 * 3^1 * 7^1$

$126 = 2^1 * 3^2 * 7^1$

Hence, the GCF is

$GCF = 2^1 * 3^1 * 7^1$

$GCF = 42$

Hence, greatest number of sack is 42

Solving (b): Number of treat in each sack.

To do this, we simply divide the number of C and L by the calculated GCF

For C:

$Treats = \frac{C}{GCF}$

$Treats = \frac{42}{42}$

$Treats = 1$

For L:

$Treats = \frac{L}{GCF}$

$Treats = \frac{126}{42}$

$Treats = 3$

<em>Hence, 1 candy bar and 3 lollipops</em>

8 0

3 years ago

There are 48 people in gym class. what fraction represents the number of people running?

DaniilM [7]

Step-by-step explanation:

c bc I know I took this last year

5 0

3 years ago