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AnnZ [28]
3 years ago
13

Triangle ABC and DEF are congruent. Find x.

Mathematics
2 answers:
Olenka [21]3 years ago
5 0

11/2. You can set x+6=3x-5 because when two triangles are congruent then all their corresponding sides and angles are congruent. Then solve for x and you get x=11/2

frosja888 [35]3 years ago
3 0
Since ABC is congruent to DEF we know that side AB is congruent to side DE. Set up the equations for both sides to equal one another (x + 6 = 3x - 5). Solve to find “x”:
- 6 = 2x - 5
- 11 = 2x
- x = 5.5
Hope this helped :)
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Step-by-step explanation:

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a store sold a case of scented candles for$17.85 that had been marked up 110%. what was the original price
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You are given that cos(A)=−35, with A in Quadrant II, and cos(B)=817, with B in Quadrant I. Find cos(A−B). Give your answer as a
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<h3>How to simply the identity</h3>

Expand cos(A - B) with the identity

You get, cos(A - B) = cos(A) cos(B) + sin(A) sin(B)

Since A is in quadrant II, so sin(A) > 0,

B is in quadrant I, so sin(B) > 0.

Using the Pythagorean identity, we get

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Make sin A the subject of formula

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Repeat the same for the second value

sin A^{2} = \sqrt{(1- 8/17)^2}

sin A = 15/17

Substitute values into cos(A - B)

cos(A - B) =  cos(A) cos(B) + sin(A) sin(B) = (-3/5) * 8/17 + 4/5 * 15/17

cos (A - B) = 36/85

Therefore, cos (A - B) is 36/85

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

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Can u attach the image pls

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