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AnnZ [28]
3 years ago
13

Triangle ABC and DEF are congruent. Find x.

Mathematics
2 answers:
Olenka [21]3 years ago
5 0

11/2. You can set x+6=3x-5 because when two triangles are congruent then all their corresponding sides and angles are congruent. Then solve for x and you get x=11/2

frosja888 [35]3 years ago
3 0
Since ABC is congruent to DEF we know that side AB is congruent to side DE. Set up the equations for both sides to equal one another (x + 6 = 3x - 5). Solve to find “x”:
- 6 = 2x - 5
- 11 = 2x
- x = 5.5
Hope this helped :)
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Nicholas is buying shirts for his baseball team. He will pay $8.75 for each shirt plus a one-time fee of $25 for the design. Wri
Margaret [11]

Answer:

Y = 8.75x + 25

Step-by-step explanation:

3 0
3 years ago
7. If the longer leg of a right triangle is twice as long as the shorter leg, what is the ratio of
kicyunya [14]

Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.

Step-by-step explanation:

I suppose that the "legs" of a triangle rectangle are the cathati.

if L is the length of the shorter leg, 2*L is the length of the longest leg.

Now you can remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus)

Then there is one acute angle calculated as:

Tan(θ)  =  (shorter leg)/(longer leg)

Tan(φ) = (longer leg)/(shorter leg)

And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.

Then we need to find θ and φ.

Tan(θ) = L/(2*L)

Tan(θ) = 1/2

θ = Atan(1/2) = 26.57°

Tan(φ) = (2*L)/L

Tan(φ) = 2

φ = Atan(2) = 63.43°

Then the ratio between the larger acute angle and the smaller acute angle is:

R = (63.43°)/(26.57°) = 2.39

This means that the larger acute angle is 2.39 times the smaller acute angle.

5 0
3 years ago
According to ​Lambert's law​, the intensity of light from a single source on a flat surface at point P is given by Upper L equal
malfutka [58]

Answer:

(a) L = k*(1 - sin^{2}(\theta))        

(b) L reaches its maximum value when θ = 0 because cos²(0) = 1

Step-by-step explanation:

Lambert's Law is given by:

L = k*cos^{2}(\theta)   (1)

(a) We can rewrite the above equation in terms of sine function using the following trigonometric identity:

cos^{2}(\theta) + sin^{2}(\theta) = 1

cos^{2}(\theta) = 1 - sin^{2}(\theta)  (2)

By entering equation (2) into equation (1) we have the equation in terms of the sine function:

L = k*(1 - sin^{2}(\theta))        

(b) When θ = 0, we have:

L = k*cos^{2}(\theta) = k*cos^{2}(0) = k  

We know that cos(θ) is a trigonometric function, between 1 and -1 and reaches its maximun values at nπ, when n = 0,1,2,3...

Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

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Solnce55 [7]
The answer is 9x^2+36x+36
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