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ELEN [110]
4 years ago
13

What is the square root of 127

Mathematics
2 answers:
Mamont248 [21]4 years ago
7 0

Answer:

11.2694276696

Step-by-step explanation:

Alika [10]4 years ago
7 0

Step-by-step explanation:

the radical can not be simplilfied

but the exact form is√127

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I need help with this question please.
Nikitich [7]
The answer would be yes. The way to solve this is by simplifying the first ratio. The first ratio should be girls to boys, which is 6:9. And since ratio can be fractions, 6:9 could be 6/9. Since 6/9 can simplify, you would get 2/3. Now we need to add the 2 girls and 3 boys back into the ratio. The ratio would then look like 8:12. And 8:12 could be 8/12, and 8/12 can be simplify, we get 2/3. So this means that the ratio stayed the same.
7 0
3 years ago
What can you divide to get 32
PtichkaEL [24]
64/2
or
96/3
or
128/4
or
160/5
or
320/10

3 0
4 years ago
Read 2 more answers
Which of the vectors below is the sum of vectors a and b, shown here?
Fofino [41]

Answer:

Option C

Step-by-step explanation:

To answer this question you must use the parallelogram method shown in the attached image.

To answer this question, use the parallelogram method as shown in the attached image.

-Place the vectors a and b at the same point of origin.

-On the tip of the vector b draws a vector a.

-On the tip of vector a to draw a vector b.

-Draw a vector "f" that goes from the origin to the corner of the parallelogram.

The vector "f" represents the sum of the vector a with the vector b.

The correct option is C


7 0
4 years ago
What is the solution to the equation?
arlik [135]
Jessi work is correct. Everyone did the work correctly as far as the method but only Jessi’s work was correct because 6/12 = 1/2


YOUR ANNSWER IS B OR JESSI’S WORK.
6 0
3 years ago
Read 2 more answers
Find an identity for cos(4t)
s344n2d4d5 [400]
We must know that \cos(2x)=2\cos^2(x)-1. So:

\cos(4t)=\cos(2\cdot2t)\\\\
\cos(4t)=2\cos^2(2t)-1\\\\
\cos(4t)=2(2\cos^2(t)-1)^2-1\\\\
\cos(4t)=2(4\cos^4(t)-4\cos^2(t)+1)-1\\\\
\cos(4t)=8\cos^4(t)-8\cos^2(t)+2-1\\\\
\boxed{\cos(4t)=8\cos^4(t)-8\cos^2(t)+1}
5 0
3 years ago
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