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Helen [10]
3 years ago
12

The first term of the a sequence equals 3. Each term in the sequence can be obtained by adding 2 from three times the value of t

he prior term.
a. List the first four terms of the sequence

b. Write the recursive formula

c. Is this an arithmetic sequence? Explain

Can anyone solve this ate you smart enough to handle my 11th graders only.​
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
I believe it’s A
Hope that helps
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DIC A student has a total of $3000 in student loans that will be paid with a 48-month installment loan with monthly payments of
gtnhenbr [62]

Answer:

The APR of the loan was 18.30%.

Step-by-step explanation:

Given that a student has a total of $ 3000 in student loans that will be paid with a 48-month installment loan with monthly payments of $ 73.94, to determine the APR of the loan to the nearest one-half of a percent the following calculation must be done:

3,000 = 100

(73.94 x 48) = X

3,000 = 100

3,549.12 = X

3,549.12 x 100 / 3,000 = X

354,912 / 3000 = X

118.30 = X

118.30 - 100 = 18.30

Therefore, the APR of the loan was 18.30%.

5 0
3 years ago
Carter has 37 coins, all nickels and dimes in his piggy bank. The value of the coins is $3.10. How many dimes does Carter have?
Sergio039 [100]
Carter has 25 dimes. He has 12 nickels.
3 0
3 years ago
Which statement is always true?
Ugo [173]
The product of two rational numbers is rational is the correct answer
8 0
3 years ago
Which is the equation in slope-intercept form for the line that passes through (3, 7)
quester [9]

Answer:

y =  -  \frac{5}{3} x + 12

Step-by-step explanation:

First, rewrite the given equation in the form of y=mx+c.

m is the gradient while c is the y-intercept.

3x-5y=8

5y= 3x -8

y =  \frac{3}{5} x -  \frac{8}{5}

Thus, the gradient of the given equation is ⅗.

The product of the gradients of perpendicular lines is -1.

(gradient of line)(⅗) = -1

gradient of line= -1 ÷⅗

gradient of line= -  \frac{5}{3}

y =  -  \frac{5}{3} x + c

To find the value of c, substitute a coordinate.

When x=3, y=7,

7 =  -  \frac{5}{3} (3) + c

7= -5 +c

c= 7+5

c= 12

Hence, the equation of the line is y =  -  \frac{5}{3} x + 12.

6 0
3 years ago
Find the sum of 7a^3 + 14a +12 and -6a^3 +12a^2 -7
SOVA2 [1]
To find the sum:

{7a}^{3} + 14a + 12  + ( {- 6a }^{3} ) + {12a }^{2}   - 7 \\  = {7a }^{3}   -  {6a}^{3}  + {12a }^{2}  + 14a + 12 - 7 \\  =  {a}^{3}  + {12a }^{2}  + 14a + 5
Therefore the answer is a^3+12a^2+14a+5.
Hope it helps!
8 0
3 years ago
Read 2 more answers
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