Answer:
You have to eliminate one of the variables when the equations are added.
A) x + 2y + z = 10
B) 2x -y +3z = -5
C) 2x -3y -5z = 27
We mulutiply A) by 2 then add it to B and C
A) 2x + 4y + 2z = 20 and the sum =
6x = 42 Luckily, the "y" and "z" variables cancel out and we find:
x = 7
Then we use x =7 in calcucating equation A) and B)
A) 2y + z = 3
B) -y + 3z = -19
THEN solve for y and z by eliminating variables.
Step-by-step explanation:
Step-by-step explanation:
you know the formulas ?
the area of a circle is : pi×r²
the circumference of a circle is : 2×pi×r
with r being the radius, which is half of the diameter.
so, here, r = 10/2 = 5 m
area = pi×r² = pi×5² = pi×25 or 25×pi m²
circumference = 2×pi×r = 2×pi×5 = 10×pi m
for the approximation we make the calculations with pi on the calculator and round to the nearest hundredth.
area = 25×pi ≈ 78.54 m²
circumference = 10×pi ≈ 31.42 m
Like fivee minuts depending on how fast you work
17=5k-2
add 2 to both sides
19=5k
divide both sides by 5
19/5=k
19/5=3 and 4/5
1/2 + 1/3 = 1/6 or <span>0.166667</span>