Answer:
65.93
Step-by-step explanation:
Okay, first lets convert the money.
100 ÷ 1.43 = 69.9300699301 (69.93)
69.93 - 4 = 65.93
Ashley has 65.93 pounds.
Hope this helps! Brainliest would be appreciated. :)
Answer:
Any set of data that satisfies the 5-Number summary: 1,6,12,16 and 19 can be represented with the box plot.
Step-by-step explanation:
<u>Interpreting Box Plots</u>
A box plot is used to present the 5-Number summary of a set of data.
The 5-Number summary consists of the following in their order of appearance on the box plot.
- Minimum Value
- First Quartile,

- Median,

- Third Quartile,

- Maximum Value
In the box plot, the following rules applies
- The whisker starts from the minimum value and ends at the first quartile.
- The box starts at the first quartile and ends at the third quartile. There is a vertical line inside the box which shows the median.
- The end whisker starts at the third quartile and ends at the maximum value.
Using these, we interpret the given box plot
A left whisker extends from 1 to 6.
- Minimum Value=1
- First Quartile =6
The box extends from 6 to 16 and is divided into 2 parts by a vertical line segment at 12.
- Median=12
- Thrid Quartile=16
The right whisker extends from 16 to 19.
Therefore any set of data that satisfies the 5-Number summary: 1,6,12,16 and 19 can be represented with the box plot.
Answer:
27,648 blades of grass
Step-by-step explanation:
512 * 54 = 27,648
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
![=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha](https://tex.z-dn.net/?f=%3DL%5Ctimes%20B%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height%5C%5C%5C%5C%3D%5B1500%5Ctimes%20%285000-2000-1500%29%5D%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%283000-1500%29%5Ctimes%20%285000-2000-1500%29%5C%5C%5C%5C%3D3375000m%5E2%3D337.5ha)
Area of region 2 = ar(DHBC)

Area of region 3 = ar(GFEH)

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Answer:
1. -141
2. 0.98
3. 62.13
Step-by-step explanation:
1. 35 - 176 -> 176 - 35 = 141, then just make it negative
2. 0.55 x 1.79 = 0.9845 -> 0.98
3. 11.38 x 5.46 = 62.1348 -> 62.13