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2 years ago

Write your answer in simplest radical form

Mathematics

2 answers:

Svetach [21]2 years ago

8 0

Answer:

$9\sqrt{3}$

Step-by-step explanation:

This is a 30-60-90 triangle.

It's good to remember this. The side length opposite to the 60 degree angle is always the base multiplied by $\sqrt{3}$

Dvinal [7]2 years ago

7 0

Answer:

9√3.

Step-by-step explanation:

tan 60 = √3

So w/9 =√3

w = 9√3

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Plsss answer this rlly need dont answer this for just points plsss :(

klio [65]

1)V=Ixwxh

=5 cm x 3 cm x 2 cm

=30 cm³

2)V=bxh

=(10m x 6m) x 4m

= 60 m² x4 m

3)V=Ixwxh

=3 cm x 3 cm x 3 cm =27 cm³

=240 m³

4 0

1 year ago

I need this fast please help me

Ahat [919]

Step-by-step explanation:

C. y= -5x + 27

D. y=2x - 15

thats all

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2 years ago

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bixtya [17]

Answer:

3 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units

Step-by-step explanation:

we know that

The isosceles trapezoid has :

Two parallel sides not equal in length called its bases (KL and NM)

Two non-parallel sides equal in length (LM and NK)

$NK=\sqrt{5}\ units$

The perimeter is equal to

$P=KL+LM+NM+NK$

substitute the values

$P=2\sqrt{2}+\sqrt{5}+\sqrt{2}+\sqrt{5}$

$P=(3\sqrt{2}+2\sqrt{5})\ units$

3 StartRoot 2 EndRoot + 2 StartRoot 5 EndRoot units

5 0

2 years ago

Read 2 more answers

Write -2i + (9 - 3i) - (6 - 10i) as a complex number in standard form. 3 - 5i 3 + 5i 3 + 16i 12 - 16i

Ierofanga [76]

Answer:

3 + 5i

Step-by-step explanation:

Given

- 2i + (9 - 3i) - (6 - 10i) ← distribute parenthesis

= - 2i + 9 - 3i - 6 + 10i ← collect like terms

= 3 + 5i

7 0

2 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

Write your answer in simplest radical form​

Write your answer in simplest radical form