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grigory [225]
3 years ago
14

Many elements in the third row and beyond in the periodic table may form more than four bonds and thus appear to have "expanded

octets." phosphorus and sulfur, for example, may form five and six covalent bonds. count up the total number of valence electrons in pcl5 and draw its lewis structure. how many valence electrons are "counted" toward the central p atom?

Chemistry
1 answer:
Blizzard [7]3 years ago
6 0

See the sketch attached for a Lewis cross-and-dot structure of PCl₅.

The central P atom ends up with ten valence electrons.

<h3>Explanation</h3>

Unlike P, Cl does not form expanded octets. Each Cl atom in PCl₅ will share one electron with a P atom. Each will form one P-Cl covalent bond and end up with a typical octet of eight electrons. Six of the eight electrons come from three non-bonding pairs (a.k.a. "lone pairs").

P is found in IUPAC group 15 of a modern periodic table. A neutral P atom has five valence electrons. Each of them goes to a P-Cl bond in PCl₅. The central P atom will end up forming five P-Cl bonds. That will gives the atom a total of ten valence electrons. That is two electrons more than a typical octet- hence the name "expanded octet".

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A 0.04328 g sample of gas occupies 10.0-mL at 294.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C
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Answer:

<u>The molecular formula of the gas sample = C_2Cl_2 </u>

<u>Lewis structure is shown in the image below.</u>

<u>The geometry around each carbon atom is linear.</u>

Explanation:

Given that:

Temperature = 294.0 K

V = 10.0 mL = 0.01 L ( 1 mL = 0.001 L )

Pressure = 1.10 atm

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

Applying the equation as:

1.10 atm × 0.01 L = n ×0.0821 L atm/ K mol  × 294.0 K  

⇒n = 0.0004557 mol

Given, mass = 0.04328 g

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0004557\ mole= \frac{0.04328\ g}{Molar\ mass}

<u>Molar mass of the gas sample = 94.9747 g/mol</u>

Given that:-

% of C = 25.305

Molar mass of C = 12.0107 g/mol

% moles of C = 25.305 / 12.0107 = 2.1069

% of Cl = 74.695

Molar mass of Cl = 35.453 g/mol

% moles of Cl = 74.695 / 35.453 = 2.1069

Taking the simplest ratio for C and Cl as:

2.1069 : 2.1069  = 1 : 1

<u>The empirical formula is = CCl</u>

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 35.5 = 47.5 g/mol

Molar mass = 94.9747 g/mol

So,  

Molecular mass = n × Empirical mass

94.9747 = n × 47.5

⇒ n = 2

<u>The molecular formula of the gas sample = C_2Cl_2 </u>

Also,

Valence electrons of carbon = 4

Valence electrons of Chlorine = 7  

The total number of the valence electrons  = 4*2 + 7*2 = 22

The Lewis structure is drawn in such a way that the octet of each atom in the molecule is complete. So,  

The Lewis structure is shown in the image below.

According to the theory, the atoms will form a geometry in such a way that there is minimum repulsion and maximum stability.  The carbon atoms are sp hybridized.

<u>So, it is of linear shape.</u>

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4 years ago
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Answer:

3.840 atm

Explanation:

We use Boyle's law, which relates the pressure (P) and the volume (V) of a gas at a constant temperature. The change from initial P and V (P₁ and V₁) to final P and V (P₂ and V₂) is expressed as:

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We have the following data:

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V₁= 200.0 mL

V₂ = 50.0 mL

Thus, we introduce the data in the equation and calculate the final pressure P₂:

P₂ = P₁V₁/V₂= (0.960 atm x 200.0 mL)/50.0 mL = 3.840 atm

Therefore, a pressure of 3.840 atm is needed to reduce the volume of the gas from 200.0 mL to 50.0 mL.

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