Question

When potassium chlorate decomposes it produces potassium chloride and oxygen gas. If 223.65 g of potassium chloride was produced, how much potassium chlorate did the reaction start with?

Answer 1

Answer:

367.7466 g of potassium chlorate is produced.

Explanation:

Given data:

223.65 g of potassium chloride is produced

Question: How much potassium chlorate did the reaction start with, mKClO₃ = ?

The balanced reaction:

2KClO₃ → 2KCl + 3O₂

Information needed:

Molecular weight of KClO₃ = 122.5 g/mol

Molecular weight of KCl = 74.5 g/mol

Molecular weight of O₂ = 32 g/mol

You can see in the reaction that 2 moles of KClO₃ gives 2 moles of KCl.

Mass of KClO₃:

$m_{KClO_{3} } =2*122.5=245g$

Mass of KCl:

$m_{KCl } =2*74.5=149g$

245 g KClO₃ --------- 149 g KCl

X g KClO₃ ------------- 223.65 g KCl

$X=m_{KClO_{3} } =\frac{245*223.65}{149} =367.7466g$