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harina [27]
2 years ago
5

0.2(3k+1)=-0.4-(-0.2-0.1K)

Mathematics
1 answer:
Tanya [424]2 years ago
4 0

Answer:

k=−0.8

Step-by-step explanation:

Start with the equation: 0.2(3k+1)=-0.4-(-0.2-0.1K)

Use distributive property on each side of the equation. For the left side, distribute 0.2 into 3k and 1, and for the right side, distribute -1 into -0.2 and -0.1k. (We use a -1 because the negative sign on the outside of the parenthesis is equivalent to -1)

(0.2)(3k) + (0.2)(1) = 0.6k + 0.2

(-1)(-0.2) + (-1)(-0.1k) = 0.2 + 0.1k

New equation: 0.6k + 0.2 = -0.4 + 0.2 + 0.1k

Now we can combine like terms on the right side. (-0.4 and 0.2)

0.6k + 0.2 = 0.1k - 0.2

Now to get rid of k on one side, we can subtract 0.1k from the right side.

(0.6k - 0.1k) + 0.2 = (0.1k - 0.1k) - 0.2

0.5k + 0.2 = -0.2

Now we need to get 0.5k by itself, so we'll subtract the 0.2 on both sides.

0.5k + (0.2 - 0.2) = (-0.2 - 0.2)

0.5k = -0.4

To get k by itself, we must divide both sides by 0.5.

(0.5k / 0.5) = (-0.4 / 0.5)

k = -0.8

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73.

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a)

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Since we can't divide by zero, we need to find when:

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But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

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<h3>CloutAnswers</h3>
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