In order to find the answer to this question, lets first answer a simpler on and work our way up.
How many ways can we arrange 2 people in a line? Let's take a, and b as our people. We can arrange them like ab, ba. 2 ways.
How many ways can we arrange 3 people in a line? Let's take a, b, and c as our people. We can arrange them like abc, acb, bac, bca, cba, cab. 6 ways.
How many ways can we arrange 4 people in a line? Let's take a, b, c and d as our people. We can arrange them like abcd, abdc, acbd, acdb, adbc, adcb, bacd, badc, bcad, bcda, bdac, bdca, cabd, cadb, cbad, cbda, cdba, cdab, dabc, dacb, dbac, dbca, dcab, dcba. 24 ways.
From this we can take the rule x = n!, where x is the number of arrangments and n is the number of people. Following this rule we can calculate the answer to be 9! or 362 880 arrangements.
the normal distribution is a symmetric distribution with no skew. ... A left-skewed distribution has a long left tail. Left-skewed distributions are also called negatively-skewed distributions. That's because there is a long tail in the negative direction on the number line.
The rule of the equation of the line is y=mx+b but since we don't have a B so it will be y=mx so in order to solve it you need to exchange the ordered pairs X=4, y=3 so 3=m(4) so the slope which is m m=4 over 3 (4/3)
