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lbvjy [14]
2 years ago
13

I need this answer as soon as possible

Mathematics
1 answer:
wel2 years ago
3 0

The perimeter is the distance all the way around. So it's the sum of the lengths of all 4 sides.

From the picture, you can clearly see the lengths of all 4 sides.

Writum down and adum up !

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A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
OlgaM077 [116]

Answer:

H0 : u = 45

H : u not equal to 45

This is because the topic of claim or contention is that the average minutes a student need to complete the statistics exam is 45mins

8 0
3 years ago
The area a of a sector of a circle is given by A equals pi times R squared times S divided by 360 where r is the radius of the c
Setler79 [48]
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{s \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
s=angle~in\\
\qquad degrees
\end{cases}\implies 360A=s\pi r^2\implies \cfrac{360A}{\pi r^2}=s
5 0
3 years ago
Help me asnwer please
Mrac [35]
The  correct answer is 248.8
area= 248.8
3 0
3 years ago
Taras garden is 3/8 are red flowers and 3/6 are yellow flowers which is greater
serg [7]

Answer: 3/6

Step-by-step explanation:

If you convert them into decimals you get

3/8 = 0.375

3/6 = 0.5

7 0
3 years ago
Read 2 more answers
Suppose a test for diagnosing a certain serious disease is successful in detecting the disease in 95% of all persons infected, b
Dahasolnce [82]

Answer:

Step-by-step explanation:

Hello!

In the study population, there is an incidence of two diseases, a serious disease (D) and a minor disease (M).

There is a diagnostic test for the serious disease that successfully detects the disease (positive) in 95% of all persons infected (D). Symbolized P(+/D)=0.95

This test incorrectly diagnoses 4% (positive) of all healthy people (H) as having a serious disease. Symbolized P(+/H)= 0.04

And it incorrectly diagnoses 12% of all people having another minor disease as having a serious disease. Symbolized P(+/M)= 0.12

It is known in the population that:

2% of the population has a serious disease. P(D)= 0.02

90% of the population is healthy. P(H)= 0.90

8% of the population has a minor disease. P(M)= 0.08

I've attached a contingency table with the symbolized probabilities you need to calculate for each category.

Remember: Given the dependent events A and B a conditional probability of this events is defined as P(A/B)= P(A∩B)/P(B)

⇒ Then you can clear the probability of the intersection of both events as:

P(A∩B)= P(A/B)*P(B)

You can apply this to the asked probabilities:

P(+∩D)= P(+/D)*P(D)= 0.95*0.02= 0.019

P(+∩M)= P(+/M)*P(M)= 0.12*0.08= 0.0096

P(+∩H)= P(+/H)*P(H)= 0.04*0.90= 0.036

P(+) = P(+∩D) + P(+∩M) + P(+∩H)= 0.019 + 0.0096 + 0.036= 0.0646

P(-) = 1 - P(+) = 1 - 0.0646= 0.9354

P(-∩D)= P(D) - P(+∩D)= 0.02 - 0.019= 0.001

P(-∩M)= P(M) - P(+∩M)= 0.08 - 0.0096=0.0704

P(-∩H)= P(H) - P(+∩H)= 0.90 - 0.036= 0.864

Tree diagram and completed table attached below.

I hope it helps!

8 0
3 years ago
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