If ir means not, then irrational means not rational. Pi is and irrational number.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
C
Step-by-step explanation:
Given
6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation
6x + 24 = 2y + 10 ( subtract 10 from both sides )
6x + 14 = 2y ( divide all terms by 2 )
3x + 7 = y, hence
y = 3x + 7 → C
answer:
x = - 9/2
y = -10
Step-by-step explanation:
make both equations look like y =
2x-3y=21 -> -3y= -2x+21 -> y = (-2x+21)/-3 -> y = 2/3x - 7
-6x + 2y = 7 -> 2y = 6x + 7 -> y = 3x + 7/2
now make the equations equal to each other (since they both equal y)
get x
2/3x - 7 = 3x + 7/2
-7 -7/2 = 3x - 2/3x
-14/2 -7/2 = 9/3x - 2/3x
-21/2 = 7/3x
(3/7) -21/2 = x
x = (3/7) -21/2
x = - 63/14
x = - 9/2
put it back in an equation to get y
y = 3x + 7/2
y = 3(-9/2) + 7/2
y = -27/2 + 7/2
y = -20/2
y = - 10
brainly.com/question/12203001
5. 4 is in the tenths place and it is under 5 so it rounds down to 5
