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irina [24]
3 years ago
8

Marianne has 3/7 cup of sugar to bake a cake she has 3/5 cup does she have enough to make the cake yes or no

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

Answer:

Yes

Step by step explanation:

You might be interested in
A bottom of a 6 foot deep circular pool has an area of 452.4 ft. If the pool is only
inna [77]

Answer:

450.4

Step-by-step explanation:

6 0
3 years ago
Express the prime number 31 in the form 2^p − 1 where p is a prime number and as a difference of two perfect squares using the i
stellarik [79]

Answer:

31 = 2⁵ -1

31 =  16²- 15²

Step-by-step explanation:

As we know that

2¹=2

2²= 4

2³= 8

2⁴= 16

2⁵=32

So

32 = 2⁵

By subtracting 1 in bot sides

32-1 = 2⁵ -1

31 = 2⁵ -1

So

2⁵ -1 = 31

By comparing with

2^p-1

p= 5

As we know that

15²= 225

16² = 256

16²- 15² = 256-225 = 31

16²- 15²  = (16+15)(16-15)

31 =  (16+15)(16-15)

5 0
4 years ago
"We might think that a ball that is dropped from a height of 15 feet and rebounds to a height 7/8 of its previous height at each
tatyana61 [14]

Answer:

Total Time = 4.51 s

Step-by-step explanation:

Solution:

- It firstly asks you to prove that that statement is true. To prove it, we will need a little bit of kinematics:

                             y = v_o*t + 0.5*a*t^2

Where,   v_o : Initial velocity = 0 ... dropped

              a: Acceleration due to gravity = 32 ft / s^2

              y = h ( Initial height )

                             h = 0 + 0.5*32*t^2

                             t^2 = 2*h / 32

                             t = 0.25*√h   ...... Proven

- We know that ball rebounds back to 7/8 of its previous height h. So we will calculate times for each bounce:

1st : 0.25*\sqrt{15}\\\\2nd: 0.25*\sqrt{15} + 0.25*\sqrt{15*\frac{7}{8} } + 0.25*\sqrt{15*\frac{7}{8} } = 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} }\\\\3rd: 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 2*0.25*\sqrt{15*(\frac{7}{8} })^2\\\\= 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2\\\\4th: 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2 + 2*0.25*\sqrt{15*(\frac{7}{8} })^3 \\\\

= 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2 + 0.5*\sqrt{15*(\frac{7}{8} })^3

- How long it has been bouncing at nth bounce, we will look at the pattern between 1st, 2nd and 3rd and 4th bounce times calculated above. We see it follows a geometric series with formula:

  Total Time ( nth bounce ) = Sum to nth ( \frac{1}{2}*\sqrt{15*(\frac{7}{8})^(^i^-^1^) }  - \frac{1}{4}*\sqrt{15})

- The formula for sum to infinity for geometric progression is:

                                   S∞ = a / 1 - r

Where, a = 15 , r = ( 7 / 8 )

                                   S∞ = 15 / 1 - (7/8) = 15 / (1/8)

                                   S∞ = 120

- Then we have:

                                  Total Time = 0.5*√S∞ - 0.25*√15

                                  Total Time = 0.5*√120 - 0.25*√15

                                  Total Time = 4.51 s

5 0
4 years ago
Help me with this quesion
tiny-mole [99]

Answer:

3 units

Step-by-step explanation:

7 0
3 years ago
Ward finances $20,000 to purchase a car. If he gets a 2.5% interest rate regardless of loan length, how much interest will Ward
Radda [10]

You will use the formula to calculate simple interest for each period of time and then subtract the two amounts to find how much Ward will save.


I=prt

I = 20000 x 0.025 x 3

I = $1500 over 3 years

I = 20000 x 0.025 x 5

I = $2500 over 5 years

$2500-$1500 = $1000 in savings

7 0
4 years ago
Read 2 more answers
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