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crimeas [40]
3 years ago
9

What is the solution of the equation? Square root 2x+13-5=x

Mathematics
2 answers:
borishaifa [10]3 years ago
8 0
Add
5
5
to both sides of the equation.
√
2
x
+
13
=
x
+
5
2
x
+
13
=
x
+
5
To remove the radical on the left side of the equation, square both sides of the equation.
(
√
2
x
+
13
)
2
=
(
x
+
5
)
2
(
2
x
+
13
)
2
=
(
x
+
5
)
2
Simplify each side of the equation.

2
x
+
13
=
x
2
+
10
x
+
25
2
x
+
13
=
x
2
+
10
x
+
25
Solve for
x
x
.

x
=
−
2
,
−
6
x
=
-
2
,
-
6
Exclude the solutions that do not make
√
2
x
+
13
−
5
=
x
2
x
+
13
-
5
=
x
true.
x
=
−
2
IrinaVladis [17]3 years ago
6 0

Answer:

x=-8

Step-by-step explanation:

simplify it first: 2x+8=x

then get x on one side: 8=-x

then make x positive: -8=x

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yulyashka [42]

Answer:

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Step-by-step explanation:

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AysviL [449]

Given,  

∠AOE = 30°

∠DOB = 40°

So, ∠EOD = 180 - (30+40)           [angles on a straight line]

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7 0
3 years ago
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Y+2=-3(x-4)<br> Find the missing value in the solution to the equation. ( , -2)
koban [17]

Answer:

(4,-2)

Step-by-step explanation:

plug in and simplify;

y+2=-3(x-4)

-2+2=-3(x-4)

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3x=12

x=4

7 0
3 years ago
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dlinn [17]

Step-by-step explanation:

I hope you have a good day

5 0
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Point K is rotated 90°. The coordinate of the pre-image point K was (2, –6) and its image K’ is at the coordinate (−6, −2). Find
umka21 [38]

Answer:

Hello! The answer to your question will be below.

Step-by-step explanation:

The answer would be clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

THE DIRECTION OF THE ROTATION WAS CLOCKWISE.

Hope this helps! :)

⭐️Have a wonderful day!⭐️

8 0
3 years ago
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