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3 years ago

Which of the following are true

Mathematics

1 answer:

geniusboy [140]3 years ago

6 0

Answer:

A and B both seem to be true.

Step-by-step explanation:

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f(X) = 9x^3 + 2x^2 - 5x^3 - 7x + 4 and g(X) = 5x^3 - 7x + 4. what is f(X) - g(X)? Show all of your steps and write your final an

dolphi86 [110]

First we can simplify f(x) to make it a little easier. We can write it as
4x^3+2x^2-7x+4 by combining like terms

The we just subtract g(x) from f(x) and simplify
4x^3+2x^2-7x+4-(5x^3-7x+4) and remember to distribute the negative to g(x)
4x^3+2x^2-7x+4-5x^3+7x-4 (combine like terms)
-x^3+2x^2
In factored form, this becomes
-x^2(x-2)

Hope this helps

5 0

3 years ago

Read 2 more answers

Look at the attachment<br>Simplified it too <br>pls take it seriously

Phantasy [73]

$\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}$

$\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}$

$\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)$

5 0

2 years ago

Todd placed 32 square tiles along the edge of his wooden dining room table, as shown below. Note: Figure is not drawn to scale.

Flauer [41]

Answer:

The diagonal is 421.

Step-by-step explanation:

This is a difficult question. To find the diagonal, you need to find the base and the height of the square. After that, you need to make it a triangle, by using this equation; $A=\frac{1}{2} BH$ (A being area, B being base, and H being height) then find the length of the hypotenuse of the triangle, which I will do for you.

$32*13=416$ The B and H = 416. Plug it into the equation now;

$A=\frac{1}{2}(416*416)\\\\\\A=\frac{1}{2} 173,056\\\\\\A=86,528$ Now that you have done that, we know that the area of our new triangle is 86,528.

The diagonal is: $421$

8 0

3 years ago

Read 2 more answers

Show that cos3(B)+cos(B)sin2(B) = 1 sin(B)cos2(B)+sin3(B) tan(B)

Pachacha [2.7K]

Answer:

-90

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago