Not easy:
- 4 < x^4 + 4x^2 ---> 0 < x^4+4x^2+4 = (x^2+2)^2, so it is always positive. Always satisfied. Curious ...
Now the other one:
x^4+4x^2<21 --> x^4+4x^2-21 < 0 --> (x^2+2)^2 - 25 < 0
(x^2+2)^2<25 ->>> x^2+2 < 5 ---> x^2 <3,
So -sqrt(3)<x<sqrt(3) is the answer! Brainliest?
1.

The base can't be negative, therefore
.
2.

3.

Answer:
3x² – 2x – 8
=> 3x² – 6x + 4x – 8
=> 3x( x – 2 ) + 4( x – 2 )
=> ( 3x + 4 ) ( x – 2 )
Therefore,
Either, 3x + 4 = 0
3x = - 4
x = - 4/3 (Ans)
And,
x – 2 = 0
x = 2 (Ans)
The table is attached as a figure
The given equation is ⇒⇒⇒⇒ y = 2x
To solve this equation, we need to pick numbers from the table then this number will be substituted into the equation to find y
we need 3 solutions . so, we need to pick 3 numbers of x
From the table, let us choose x = 0
y = 2x
y = 2 * (0)
y = 0
From the table, let choose second value of x such as x = 1
y = 2 * (1)
y = 2
From the table, let choose third value of x such as x = -1
y = 2 * (-1)
y = -2
So, the picked three solutions are y = 0 at x = 0y = -2 at x = -1y = 2 at x = 1
700a+1200r=1000000 (then plug in the a)
700(1000) +1200r=1000000 (simplify)
700000+1200r=1000000 (subtract 700000 from both sides)
1200r=300000 (divide by 1200 on both sides)
r=250
250 pounds