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3 years ago

How to do proof problems in geometry

1 answer:

Crank3 years ago

6 0

First, start with your given. If your given has the words: bisect or midpoint, then the next step will be the definition of that.

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Look at the image for the problem :)

8_murik_8 [283]

Answer:

$\displaystyle V = 28 \pi \ ft^3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Volume of a Cylinder Formula: $\displaystyle V = \pi r^2h$

V is volume
r is radius
h is height

Step-by-step explanation:

Step 1: Define

Radius r = 2 ft

Height h = 7 ft

Step 2: Solve for V

Substitute in variables [Volume of a Cylinder Formula]: $\displaystyle V = \pi (2 \ ft)^2(7 \ ft)$
[Volume] Evaluate exponents: $\displaystyle V = \pi (4 \ ft^2)(7 \ ft)$
[Volume] Multiply: $\displaystyle V = 28 \pi \ ft^3$

5 0

3 years ago

The sides of a triangle are consecutive integers.if its perimeter is 126cm,find the lenghts of the sides.

Neko [114]

X + (x + 1) + (x + 2) = 126
3x = 123
x = 41
So the sides are 41, 42 and 43

3 0

4 years ago

Solve for e. I need help I have to hurry and turn this in!!

yarga [219]

1st option.

T9=e^2

e=sq root of T9

9 can be sq rooted to 3

hence e=3×sqroot of T

7 0

3 years ago

Translate the following into an algebraic expression: A number is 30% of 20% of the number x.

bezimeni [28]

Answer: 0.06x

Step-by-step explanation:

An algebraic expression is an expression consist of integer constants, variables, and algebraic operations.

The given statement: A number is 30% of 20% of the number x.

The required algebraic expression would be:

30% of 20% of x

$=\dfrac{30}{100}\times \dfrac{20}{100}\times x$ [we divide a percentage by 100 to convert it into decimal]

$=\dfrac{6}{100}\times x\\\\=0.06x$

Hence, the required algebraic expression would be :

0.06x

4 0

3 years ago

The area of a rectangle is 48 square centimeters and the length of the rectangle is 8 centimeters longer than the width.

Luda [366]

I hope this helps you

8 0

4 years ago