Find the volume of a sphere with a diameter of 25 cm. Approximate r as 3.14 and round your answer to the neare

Mathematics

1 answer:

never [62]3 years ago

8 0

Answer:it would be D

Step-by-step explanation:

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Graph the two lines 2x + 3y = 18 , 3x -4y > 16.

Dmitrij [34]

The domain and range for each line is all real numbers. This is because all numbers are possible to input into x and all y values exist.

The slope of the first line is -2/3 and the y intercept is 6. You can reach this conclusion by solving for y (putting it in slope intercept form).

The slope of the second one is 3/4. and the y intercept is all real numbers greater than -4. This is true because it is an inequality and you can find these numbers by solving for y.

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3 years ago

F(x)=x2+3x-5 and g(x)=x/4-6.g(x)=x/4-6

xenn [34]

Answer:

idk the answer but i use socratic by google to take pictures of the problems and find answers online, and also cymath.com is a really great place to get answers for math, i hope this helps!

Step-by-step explanation:

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3 years ago

Read 2 more answers

FIRST TO ANSWER GETS BRAINLIEST!

scZoUnD [109]

Answer:

$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

circle
PEMDAS

<h3>tips and formulas:</h3>

$\rm \:A_{shaded}= \dfrac{\theta}{360} \times \pi {r}^{2}$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
$\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
$\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
$\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$